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garik1379 [7]
3 years ago
7

two wave pulses pass each other on a string. the one traveling toward the right has a positive amplitude, while the one travelin

g toward the left has an equal amplitude in the negative direction. at the point that they occupy the same region of space at the same time a) destructive interference occurs b) a standing wave is produced c) constructive interference is produced d) a traveling wave is produced
Physics
1 answer:
oee [108]3 years ago
5 0

Answer:

a) destructive interference occurs

Explanation:

Given that two waves are traveling towards each with same magnitude of amplitude .

As we know that when two waves are superimpose then

1. If they are traveling in the same direction then the resultant wave amplitude is higher than the amplitude of any the given wave and this is known as constructive interference.

2. If they are traveling in the opposite direction then the resultant wave amplitude is lower than the amplitude of any the given wave and this is known as destructive interference.

So the answer is a.

a) destructive interference occurs

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At one point in space, the electric potential energy of a 15 nC charge is 42 μJ . Part A) What is the electric potential at this
Anastasy [175]

Answer:

Part A:

\rm 2.8\times 10^3\ Volts.

Part B:

\rm 5.6\times 10^{-5}\ J.

Explanation:

<u> Part A:</u>

  • Potential energy of charge at the given point, \rm U=42\ \mu J=42\times 10^{-6}\ J.
  • Charge, \rm q=15\ nC = 15\times 10^{-9}\ C.

The potential energy at a point due to a charge is defined as

\rm U=qV.

<em>where</em>,

V = electric potential at that point.

Therefore,

\rm V=\dfrac{U}{q}=\dfrac{42\times 10^{-6}}{15\times 10^{-9}}=2.8\times 10^3\ Volts.

<u>Part B:</u>

Now, if the charge at that point is replaced with \rm q_1 = 20\ nC = 20\times 10^{-9}\ C., then the electric potential energy at that point is given by

\rm U=q_1V = 20\times 10^{-9}\times 2.8\times 10^3=5.6\times 10^{-5}\ J.

5 0
3 years ago
What type of reaction requires the greatest energy to get started? A. fusion B. fission C. physical D. chemical
Vilka [71]
What do u mean by that

4 0
3 years ago
Read 2 more answers
Complete the following statement: When a net torque is applied to a rigid object, it always produces a:______.
Tatiana [17]

When a net torque is applied to a rigid object, it always produces a <em>change in angular velocity</em>. <em>(e.)</em>

7 0
3 years ago
Wonder Woman uses 2,000 N to lift a truck 2.3 meters in 5 seconds. How much power did she use?
tino4ka555 [31]

Answer:

she used alot

Explanation:

she would need to be very powerful if she coukd do that.. but then again its wonder woman.

(srry just so detail )

but

f=2,000

x=2.3

w=?

2,000x 2.3 =869.57

w=869.57

t=5 s

p=?

p=w/t

869.57/5=173.913

so she used 173.913 w also known as power

7 0
3 years ago
in what distance can a 1500kg automobile be stopped if the brake is applied when the speed is 20m/s and the coefficient of slidi
natali 33 [55]

1) The braking force is provided by the frictional force, which is given by:

F_f=\mu m g

where

\mu=0.7 is the coefficient of friction

m=1500 kg is the mass of the car

g=9.81 m/s^2 is the gravitational acceleration


Substituting numbers into the equation, we find

F_f= (0.7)(1500 kg)(9.81 m/s^2)=10301 N


2) The work done by the frictional force to stop the car is equal to the product between the force and the distance d:

W=-F_fd (1)

where we put a negative sign because the force is in the opposite direction of the motion of the car.


3) For the work-energy theorem, the work done by the frictional force is equal to the variation of kinetic energy of the car:

\Delta K=K_f -K_i =W (2)

The final kinetic energy is zero, so the variation of kinetic energy is just equal to the initial kinetic energy of the car:

\Delta K=-K_i=-\frac{1}{2}mv^2=-\frac{1}{2}(1500 kg)(20 m/s)^2=-300000 J


4) By equalizing eq. (1) and (2), we find the distance, d:

-K_i = -Fd

d=\frac{K_i}{F}=\frac{300000 J}{10301 N}=29.1 m

8 0
3 years ago
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