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Tju [1.3M]
3 years ago
6

Process A: Waves in a river lift rocks which crash down to the river bed and break

Chemistry
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

Process B

Explanation:

Process B represents chemical weathering.

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Determine the number of electrons transferred in the balanced chemical equation. h2o
melomori [17]
I think the answer to this question is three or 3
5 0
3 years ago
This chemical equation represents a chemical reaction. 2HNO3+Na2SO3-2NaNO3+H2O+SO2
muminat

Answer:

D. Na₂SO₃

Explanation:

The given equation is:

         2HNO₃ + Na₂SO₃  → 2NaNO₃  + H₂O + SO₂

The reaction equation is shown above. In chemical reactions, the left hand side is made up of the reactants and the right hand side is made up of the products.

 The reactants in the equation are:

     HNO₃ and Na₂SO₃

6 0
3 years ago
Read 2 more answers
Which of the following procedures increases the average kinetic energy
Sever21 [200]

Answer:

Cooling Steam at 100 C to ice at 0 C

Explanation:

8 0
3 years ago
PLEASE ANSWER QUICKLY!! 25. Which gas sample contains a total of 3.0 x 1023 molecules?
nevsk [136]

Answer:

14 g of N2

Explanation:

If we look at the options, we will notice that the correct answer needs to be a gas that has about half of the molecular mass of the gas.

If we consider nitrogen gas whose molecular mass is 28g/mol, half of the molecular mass is 14 g.

So;

28g of N2 contains 6.02 × 10^23 molecules of N2

14g of N2 contains 14 × 6.02 × 10^23 /28

= 3.0 x 10^23

4 0
3 years ago
Ten kilograms of R-134a fill a 1.595-m3 weighted piston-cylinder device at a temperature of −26.4°C. The container is now heated
Tju [1.3M]

Explanation:

The given data is as follows.

    Mass of refrigerant, m = 10 kg

  Volume of the refrigerant, V = 1.595 m^{3}

Formula for specific volume of the refrigerant is as follows.

        v = \frac{V}{m}

           = 0.1595 m^{3}/kg

So, at -26.4^{o}C specific volume will be within v_{f} and v_{g} and pressure is constant.

The fluid will be in super-heated state at temperature 100^{o}C and at T = -26.4^{o}C pressure 1 bar = 0.1 MPa.

According to super-heated tables, the specific volume is v = 0.30138 m^{3}/kg.

Hence, the final volume will be calculated as follows.

               V_{f} = v \times m

                         = 0.30138 m^{3}/kg \times 10 kg

                         = 3.0138 m^{3}

Thus, we can conclude that final volume of the R-134a is 3.0138 m^{3}.

7 0
3 years ago
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