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Aliun [14]
3 years ago
14

Which statements best describes a major difference types of elements

Chemistry
1 answer:
Sever21 [200]3 years ago
6 0

Answer:

The atoms of different elements have different numbers of protons and electrons.

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Thermochemistry
max2010maxim [7]
THe Answer is 105 J

hope this helps and please brainliest, I was first :)
4 0
3 years ago
A client who weighs 70 kg is receiving a solution of 0.9% sodium chloride (normal saline) 500 ml with dopamine 800 mg at 5 ml/ho
nordsb [41]

The mcg/kg/minute the client is receiving is 1.904 mcg/kg/min whose weight is 70 kg.

<h3>What does mcg kg mean?</h3>

1 milligram (mg) = 1000 micrograms (mcg) or 0.001 grams (g) 1 g = 1000 mg 1 kilogram (kg) = 1000 g 1 kg = 2.2 pound (lb) 1 liter (L) = 1000 milliliters (mL)

The number of mcg/kg/minute = flow rate × concentration ÷ mass of client

Flow rate = 12 ml/hour = 12 ml/hour × 1 hr/60 min = 0.2 ml/min

Concentration = mass of dopamine/volume

where

mass of dopamine = 800 mg and

volume =  500 ml

Concentration =800 mg/500 ml

= 1.6 mg/ml

= 1.6 mg/ml × 1000 mcg/mg

= 1600 mcg/ml

mass of client = 70 kg

Calculating mcg/kg/minute

So, substituting the variables into the equation, we have

mcg/kg/minute = flow rate × concentration ÷ mass of client

mcg/kg/minute = 0.08 ml/min × 1600 mcg/ml ÷ 70 kg

mcg/kg/minute = 320 mcg/min ÷ 70 kg

mcg/kg/minute = 1.904 mcg/kg/min

Thus, the mcg/kg/minute the client is receiving is 1.904 mcg/kg/min

Learn more about mcg/kg/minute here:

brainly.com/question/4253005

#SPJ1

7 0
1 year ago
Why is foam fight chemical or a physical change
nata0808 [166]

Answer:

Foam fight is a chemical change.

Explanation:

Please give me brainliest :)

4 0
3 years ago
Read 2 more answers
What is the molarity of a NaCl stock used to make 750 ml of a dilute 10 mM solution if 5 ml of the concentrated solution was use
ch4aika [34]

Explanation:

The given data is as follows.

          M_{1} = 10 mM = 10 \times 10^{-3} M

          V_{1} = 750 ml,           V_{2} = 5 ml

          M_{2} = ?

Therefore, calculate the molarity of given NaCl stock as follows.

                  M_{1} \times V_{1} = M_{2} \times V_{2}

                  10 \times 10^{-3} \times 750 ml = M_{2} \times 5 ml

                   M_{2} = 1.5 M

Thus, we can conclude that molarity of given NaCl stock is 1.5 M.        

7 0
3 years ago
Given a solution with a pOH of 13.6, what is the [OH-] of the solution?
Lelechka [254]
10^-13.6 = 2.51x10^-14
8 0
3 years ago
Read 2 more answers
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