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ikadub [295]
4 years ago
12

The mass of a football player who weighs 1250N

Physics
1 answer:
Readme [11.4K]4 years ago
5 0


Ah hah !  That depends on where he weighs 1250N, because
weight depends not only on mass but also on the local gravity.
So the same mass can have different weights in different places,
and the same weight can indicate different mass in different places.

       Weight = (mass) x (acceleration of gravity) .

Note:  1250N  is almost exactly  281 pounds.

-- If he weighs 1250N on Mars, then his mass is  336.8 kg.

-- If he weighs 1250N on Earth, then his mass is  127.5 kg.

-- If he weighs 1250N on the Moon, then his mass is  770.2 kg.

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How long would it take an object to stop if it is moving at 15m/s and has an acceleration -0.5m/s^2? Please show your work.
elena-14-01-66 [18.8K]

Time = 15/-0.5 = 14.5/-0.5 = 14.5s

The answer is 14.5s

Sorry no one would answer it sooner.

3 0
3 years ago
During heavy rain, a section of a mountainside measuring 2.3 km horizontally (perpendicular to the slope), 0.75 km up along the
Jobisdone [24]

Answer:

93328 kg

Explanation:

\rho = Density of mud = 1900 kg/m³

Volume of the cuboid is given by

V=2300\times 750\times 1.4\\\Rightarrow V=2415000\ m^3

Volume is also given by

V=Al\\\Rightarrow l=\dfrac{V}{A}\\\Rightarrow l=\dfrac{2415000}{520\times 520}\\\Rightarrow l=8.9312\ m

The length of the cuboid is 0.89312 m

For the small volume

V_a=al\\\Rightarrow V_a=5.5\times 8.9312\\\Rightarrow V_a=49.12\ m^3

Mass is given by

m=\rho V_a\\\Rightarrow m=1900\times 49.12\\\Rightarrow m=93328\ kg

The mass of the mud is 93328 kg

6 0
3 years ago
A scuba tank, when fully submerged, displaces15.7 Lof seawater. The tank itself has a mass of13.5kgand, when "full," contains 3.
CaHeK987 [17]

Answer:

Explanation:

A ) weight of air + weight of tank = 013.5 + 3.2

= 16.7 kg

volume of air

= 3.2 / 1.225 = 2.61 m³

= volume of water displaced = 2.61 m³

weight of water displaced = 2.61 x 1025

= 2675.25 kg

buoyant force = 2675.25 kg

buoyant force = weight of displaced sea water

= volume of displaced sea water x density

= 15.7 x 10⁻³ x 1025

= 16.0925 kg

net force =  buoyant force - weight

= 2675.25 - 16.7

= 2658.55 kg

B ) net force will be in downward direction as weight is higher .

C ) weight of tank + weight of water in it

= 13.5 + 15.7 x 10⁻³ x 1025

= 13.5 + 16.0925

= 29.5925 kg

buoyant force = 16.0925 kg

net force = 29.5925 - 16.0925

= 13.5 kg

D ) net force down wards

7 0
3 years ago
A skier starting from rest skis straight down a slope 50 meters long in 5.0 seconds. What is the magnitude of the acceleration?
g100num [7]
So the problem ask to calculate the magnitude acceleration of the skier skiing down a slope of 50 meters long in 5 seconds. So base on that fact, the acceleration would be equals to 4 meters/seconds^2. I hope you are satisfied with my answer and feel free to ask for more 
4 0
3 years ago
Gravitational Potential Energy: You and your friend, who weighs the same as you, want to go to the top of the Eiffel Tower. Your
ololo11 [35]

Answer:

Gravitational Potential Energy of both will be equal

Explanation:

The gravitational potential energy is given by the following formula:

P.E = mgh

where,

P.E = Gravitational Potential Energy

m = mass of object

g = acceleration due to gravity

h = height of object

Therefore, the gravitational potential energy of an object depends only upon the height of the object and its mass.

Since, both masses and the heights achieved by both people is equal. <u>Therefore, their gravitational potential energies will also be equal</u>

7 0
3 years ago
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