I think it is electron. Electrons are located outside of the nucleus
E=kq/r^2
q=(E*r^2)/k
q=(.086N/C)(1.7m^2)/(8.99*10^9N*m^2/C^2)
q=2.76*10^-11 C
q=2.8*10^-11 C
The elastic potential energy stored in the car's spring during the process is 3.75 J
<h3>Determination of the spring constant</h3>
From the question given above, the following data were obtained:
K = F/e
K = 15 / 0.5
K = 30 N/m
<h3>Determination of the potential energy</h3>
- Spring constant (K) = 30 N/m
PE = ½Ke²
PE = ½ × 30 × 0.5²
PE = 15 × 0.25
PE = 3.75 J
Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J
Learn more about energy stored in spring:
brainly.com/question/4280346
Answer:
2.92682 m

250000000000 Hz

0.21126 m
0.12244 m
Explanation:
c = Speed of light = 
= Wavelength
f = Frequency
Wavelength is given by

The wavelength is 2.92682 m
Frequency is given by

The frequency is 

The frequency is 250000000000 Hz

The wavelength is 

The wavelength is 0.21126 m

The wavelength is 0.12244 m