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Natali [406]
2 years ago
10

What are the functions of stems? (Select all that apply.)

Physics
1 answer:
yuradex [85]2 years ago
6 0

Explanation:

<em>A.</em><em> </em><em>Stems</em><em> absorb water from the soil.</em>

<em>B.</em><em> </em><em>Stems</em><em> transport water and minerals.</em>

<em><u>Hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em>

<em><u>have</u></em><em><u> a</u></em><em><u> good</u></em><em><u> day</u></em><em><u>.</u></em>

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Answer:

0 J

Explanation:

given,

mass of the ball = 5 kg

radius of the horizontal circle = 0.5 m

tension in the string = 10 N

Work done = ?

Work done by the tension in the circular path will be equal to zero.

This is because body moves in circular path, the centripetal force act along the radius of the circle and motion is right angle to the tension on the string.

so, work done = F s cos θ

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8 0
3 years ago
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zaharov [31]
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4 years ago
If it requires 8.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re
jenyasd209 [6]

Answer:

The amount of work done required to stretch spring by additional 4 cm is 64 J.

Explanation:

The energy used for stretching spring is given by the relation :

E = \frac{1}{2}kx^{2}           .......(1)

Here k is spring constant and x is the displacement of spring from its equilibrium position.

For stretch spring by 2.0 cm or 0.02 m, we need 8.0 J of energy. Hence, substitute the suitable values in equation (1).

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Substitute 0.06 m for x and 4 x 10⁴ N/m for k in equation (1).

E = \frac{1}{2}\times4\times10^{4}\times (0.06)^{2}

E = 72 J

But we already have 8.0 J. So, the extra energy needed to stretch spring by additional 4 cm is :

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7 0
3 years ago
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Phantasy [73]
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Ilia_Sergeevich [38]

Answer:

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