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3 years ago

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If A is the center of the circle, then which statement explains how segment GH is related to segment FH? A. segment GH ≅ segment

FH because arc EF ≅ arc GF B. segment GH ≅ segment FH because the inscribed angles that create the segments are congruent. C. segment GH ≅ segment FH because the tangents that create the segment FG share a common endpoint. D. segment GH ≅ segment FH because segment FG is perpendicular to a radius of circle A.

1 answer:

koban [17]3 years ago

4 0

Answer:a

Step-by-step explanation:

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Please help i will mark brainliest

Evgen [1.6K]

Answer:

2. $\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$

3. $\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]$

4. $\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]$

Step-by-step explanation:

2. This matrix is easy, as it just requires addition.

$\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]$ = $\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$

3. This matrix requires for the matrices to be multiplied first, then added.

$\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]$ + $\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]$ = $\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]$

4. Here we can add the last 2 matrices to find x.

$\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]$ + $\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]$ = $\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]$

Hope this helps! (Please consider giving brainliest)

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3 years ago

Select all the expressions that are equivalent to (2)^n+³

eimsori [14]

Answer:

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

$a^{m}$ × $a^{m}$ = $a^{m+n}$
$(a^{m})^{n}$ = $a^{m*n}$

Now let us find the equivalent expressions of $(2)^{n+3}$

A.

∵ 4 = 2 × 2

∴ 4 = $2^{2}$

∴ $(4)^{n+2}$ = $(2^{2})^{n+2}$

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴ $(4)^{n+2}$ = $(2)^{2n+4}$

B.

∵ 4 = 2 × 2

∴ 4 = 2²

∴ $4(2)^{n+1}$ = 2² × $(2)^{n+1}$

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴ $4(2)^{n+1}$ = $(2)^{n+3}$

C.

∵ 8 = 2 × 2 × 2

∴ 8 = 2³

∴ $8(2)^{n}$ = 2³ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴ $8(2)^{n}$ = $(2)^{n+3}$

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = $2^{4}$

∴ $16(2)^{n}$ = $2^{4}$ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴ $16(2)^{n}$ = $(2)^{n+4}$

E.

$(2)^{2n+3}$ is in its simplest form

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

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Answer:

2

Step-by-step explanation:

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Step-by-step explanation:

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bixtya [17]

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