Answer:
They affect the weathering of molecules and atoms.
Explanation:
Answer:
T₂ = 242 K
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 125 mL
Initial pressure = 1.77 atm
Initial temperature = 213 °C (213 +273 = 486 K)
Final volume = 136 mL
Final pressure = 0.810 atm
Final temperature = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂T₁ / P₁V₁
T₂ = 0.810 atm × 136 mL × 486 K / 1.77 atm× 125 mL
T₂ = 53537.76 atm .mL. K / 221.25 atm . mL
T₂ = 242 K
There are 4 significant figures
Answer:
749 grams CO₂
Explanation:
To find the amount of carbon dioxide produced, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass from periodic table), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio via reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be in the numerator. The final answer should have 3 significant figures because the given value (250. grams) has 3 sig figs.
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.008 g/mol)
Molar Mass (C₃H₈): 44.094 g/mol
1 C₃H₈ + 5 O₂ ---> 3 CO₂ + 4 H₂O
Molar Mass (CO₂): 12.01 g/mol + 2(16.00 g/mol)
Molar Mass (CO₂): 44.01 g/mol
250. g C₃H₈ 1 mole C₃H₈ 3 moles CO₂ 44.01 g
------------------ x ---------------------- x ---------------------- x -------------------- =
44.094 g 1 mole C₃H₈ 1 mole CO₂
= 749 grams CO₂
