Answer:
The molarity of the acid solution = 0.226 M
Explanation:
<u>Step 1:</u> Data given
Volume of nitric acid = 9.96 mL = 0.00996 L
Volume strontium hydroxide = 13.25 mL = 0.01325 L
Molarity of strontium hydroxide = 0.085 M
<u>Step 2</u>: The balanced equation
2HNO3 + Sr(OH)2 → Sr(NO3)2 + 2H2O
For 2 moles HNO3 we need 1 mole of Sr(OH)2 to produce 1 mole Sr(NO3)2 and 2 moles H2O
<u>Step 3:</u> Calculate the molarity of the acid solution
n2 * C1 * V1 = n1*C2*V2
⇒ with n2 = the number of moles of Sr(OH)2 = 1 moles
⇒ with C1 = the molarity of HNO3 = TO BE DETERMINED
⇒ with V1 = the volume of HNO3 = 0.00996 L
⇒ with n1 = the number of moles of HNO3 = 2 moles
⇒ with C2 = the molarity of Sr(OH)2 = 0.085 M
⇒ with V2 = the volume of Sr(OH)2 = 0.01325 L
1*C1 * 0.00996 L = 2 * 0.085 M * 0.01325 L
C1 = (2*0.085*0.01325) / 0.00996
C1 = 0.226 M
The molarity of the acid solution = 0.226 M