Answer:
ΔS > 0 only for choice E: CH4(g) + H2O (g) → CO(g) + 3 H2(g)
Explanation:
Our strategy in this question is to use the trend in entropies :
S (solids) less than S (liquids) less than S (gases)
Also we have to look for the molar quanties involved of each state and their change to answer the question:
A. N2(g) + 3 H2(g) → 2 NH3(g)
Here we have 4 moles gases going to 2 moles of products, so the change in entropy is negative.
B. Na2CO3(s) + H2O(g) + CO2(g) → 2 NaHCO3(s)
The change in entropy is negative since we have 2 mol gases in the reactants and zero in the products.
C. CH3OH(l) → CH3OH(s)
A liquid has a higher entropy than a solid so ΔS is negative
D. False see A,B,C
E. The change in moles of gases is 4 - 2= 2, therefore ΔS is greater than O.
Answer:
C. A persons lost limb can be replaced with an advanced robotic limb
✅(D) a molecular solid. These compounds have low melting points, low electrical conductivity, etc, so this is the correct answer.
IamSugarBee
At STP, the volume of Cl2 is 22.4 L/mol.
11.5 L Cl2 * (1 mol Cl2/ 22.4 L Cl2)= 115/224 mol Cl2.
115/224 mol Cl2* (70.90 g Cl2/ 1 mol Cl2)= 36.4 g Cl2.
The final answer is 36.4 g Cl2.
Hope this helps~
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