3 years ago

What is the partial pressure of the third gas, helium?

Chemistry

1 answer:

Fofino [41]3 years ago

8 0

<span>If my math is correct .768 g </span>

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The final temperature at 1050 mmHg is 134.57 $^{\circ}C$ or 407.57 Kelvin.

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Initial temperature = T = 55 $^{\circ}C$ = 328 K

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Assuming final to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg

The final temperature is obtained by following relation at constant volume

$\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}$

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