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Mariulka [41]
4 years ago
6

In space, a stationary light source emits green light at a frequency of 5.50*10^14Hz. A spaceship approaches the light at a spee

d 1.50*10^7m/s. What is the frequency of the light that is perceived aboard the spaceship. (the speed of light is 3.00*10^8m/s) A.6.08*10^14Hz B.4.98*10^14Hz C.5.50*10^14Hz D.6.77*10^14Hz
Physics
1 answer:
VashaNatasha [74]4 years ago
4 0

A spaceship approaches the light at a speed 1.50*10^7m/s which is about 5% of light speed. So the green light will shift towards the blue end of spectrum due to "blue shift."

The frequency should be higher which rules out option B and C. Looking at the magnitude of change, the correct answer should be A.6.08*10^14Hz,

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Which sound wave-object interaction is used by animals in echolocation?
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The answer is reflection
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3 years ago
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Answer:

None

Explanation:

Subatomic particles are the particles which are very smaller than the atoms. Elementary particles are the examples of subatomic particles.

Elementary particles are the particles without any sub-structure which means they are not composed of other particles.

The elementary particles are classified into three categories which are discussed below:

(1) Quarks: up, down, top, bottom, strange, and charm.

(2) Leptons: muon, muon neutrino, electrons, electron neutrino,  tau, tau neutrino.

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Therefore, in the given list there is no meson.

3 0
3 years ago
Calculate the amount of heat (in kJ) required to convert 97.6 g of water to steam at 100° C. (The molar heat of vaporization of
Ratling [72]

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221.17 kJ

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N = 97.6 ÷ 18

Q=molar heat *moles

Q = (40.79) * (97.6 ÷ 18)

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4 0
3 years ago
Is the alien theory a scientific claim? Why or why not?
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8 0
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Answer:

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Explanation:

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where

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m is the mass of the satellite

r is the distance of the satellite from the Earth's centre

Here we have

m = 700 kg

r=2.4\cdot 10^6 m

Substituting into the equation, we find:

F=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(700)}{(2.4\cdot 10^6)^2}=4.8 \cdot 10^4 N

<em>Note that the distance mentioned in the problem (2.4 x 10^6 meters) is not realistic, since it is less than the radius of the Earth (6.37 x 10^6 meters).</em>

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