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rodikova [14]
2 years ago
12

If a student wanted to find a diagram of the human reproductive system in his/her science textbook, which part of the book shoul

d be looked at FIRST?
A) appendix
B) bibliography
C) glossary
D) index
Chemistry
2 answers:
kenny6666 [7]2 years ago
7 0
I got index basically the index since it’s the first part of the page that starts out gives a recap of everything
Katena32 [7]2 years ago
5 0

Answer:D)index

Explanation:

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Umnica [9.8K]
Yes, because beryllium is less dense and harder than oxygen.
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3 years ago
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15 points + brainliest pls help :(
Komok [63]

Answer:

27 g

Explanation:

M(C6H12O6) = 6*12 + 12*1 + 6*16 = 180 g/mol

100 mL = 0.1 L solution

1.5 M = 1.5 mol/L

1.5 mol/L * 0.1 L = 0.15 mol  C6H12O6

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2 years ago
If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above
jasenka [17]

Answer : The density of an object is, 2g/cm^3

Solution : Given,

Mass of an object = 60 g

Volume of an object = 30cm^3

Formula used :

\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}

Now put all the given values in this formula, we get the density of an object.

\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3

Therefore, the density of an object is, 2g/cm^3

6 0
3 years ago
How many moles of sodium ions are present in 0.25 kg of a 2.0 m solution of sodium chloride in water
LenKa [72]

0.50 is the answer on edge

8 0
3 years ago
en un recipiente se tiene 800 g de una solución al 35% en masa de ácido sulfuroso, de la cual se evapora 80ml de agua. ¿cuál es
Alinara [238K]

The mass percent of sulfurous acid in the new solution : 38.9%

<h3>Further explanation</h3>

<em>In a container you have 800 g of a 35% by mass solution of sulfurous acid, from which 80 ml of water evaporates. What is the mass percent of sulfurous acid in the new solution? data: density of water is 1g / ml.</em>

<em />

solution 1

composition :

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\tt 0.35\times 800~g=280~g

  • water :

\tt 800-280=520~g

solution 2(new solution)

composition :

  • water

\tt 520-(80~ml\times 1~g/ml)=440~g

  • Total mass of new solution after water evaporated

\tt 280(acid)+440(water)=720~g

  • %mass of acid in a new solution

\tt \dfrac{280}{720}\times 100\%=38.9\%

5 0
2 years ago
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