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lara [203]
3 years ago
9

To save time you can approximate the initial volume of water to ±1 mL and the initial mass of the solid to ±1 g. For example, if

you are asked to add 23 mL of water, add between 22 mL and 24 mL. Which metals in each of the following sets will have equal density? *20.2 g gold placed in 21.6 mL of water and 12.0 g copper placed in 21.6 mL of water. *20.2 g silver placed in 21.6 mL of water and 12.0 g silver placed in 21.6 mL of water. *15.2 g copper placed in 21.6 mL of water and 50.0 g copper placed in 23.4 mL of water. *15.4 g gold placed in 20.0 mL of water and 15.7 g silver placed in 20.0 mL of water. *20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water. *11.2 g gold placed in 21.6 mL of water and 14.9 g gold placed in 23.4 mL of water.
Chemistry
2 answers:
WARRIOR [948]3 years ago
6 0

Answer:

20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water

Explanation:

Since the density formula is mass divided volume, you can calculate the density of each of the components of the group and see which of all the groups are equal

In the group

density Ag=20.2 g silver/21.6ml H2O=0.9352g/ml

density Cu=20.2 g copper/21.6ml H2O=0.9352 g/ml

KengaRu [80]3 years ago
5 0

<u>Answer:</u> The correct answer is 20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water

<u>Explanation:</u>

Density of a substance is defined as the ratio of its mass and volume. The chemical equation representing density of a substance is:  

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

Density is considered as an intensive property. Intensive property is the property that does not depend on the amount of substance. It remains same.

If the masses and volume of different substances are same, they will have same density.

For 20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water:

Density of silver = \frac{20.2g}{21.6mL}=0.935g/mL

Density of copper = \frac{20.2g}{21.6mL}=0.935g/mL

Hence, the correct answer is 20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water

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Cryolite, Na3AlF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide. Balance the equation f
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<u>Answer:</u> The mass of cryolite produced is 51.48 kg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For aluminium oxide:</u>

Given mass of aluminium oxide = 12.5 kg = 12500 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of aluminium oxide = 101.96 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium oxide}=\frac{12500g}{101.96g/mol}=122.6mol

  • <u>For NaOH:</u>

Given mass of NaOH = 55.4 kg = 55400 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of NaOH}=\frac{55400g}{40g/mol}=1389mol

  • <u>For HF:</u>

Given mass of HF = 55.4 kg = 55400 g

Molar mass of HF = 20 g/mol

Putting values in equation 1, we get:

\text{Moles of HF}=\frac{55400g}{20g/mol}=2770mol

For the given chemical reaction:

Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O(g)

By Stoichiometry of the reaction:

1 mole of aluminium oxide reacts with 6 moles of sodium hydroxide and 12 moles of HF.

So, 122.6 moles of aluminium oxide will react with (6\times 122.6)=735.6mol of sodium hydroxide and (12\times 122.6)=1471.2mol of HF

As, given amount of NaOH and HF is more than the required amount. So, they are considered as an excess reagent.

Thus, aluminium oxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 122.6 moles of aluminium oxide will produce = \frac{2}{1}\times 122.6=245.2mol of cryolite

Now, calculating the mass of cryolite by using equation 1:

Molar mass of cryolite = 209.94 g/mol

Moles of cryolite = 245.2 mol

Putting values in equation 1, we get:

245.2mol=\frac{\text{Mass of cryolite}}{209.94g/mol}\\\\\text{Mass of cryolite}=(245.2mol\times 209.94g/mol)=51477.3g

Converting this into kilograms, we use the conversion factor:

1 kg = 1000 g

So, 51477.3 g\times (\frac{1kg}{1000g})=51.48kg

Hence, the mass of cryolite produced is 51.48 kg

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