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lara [203]
3 years ago
9

To save time you can approximate the initial volume of water to ±1 mL and the initial mass of the solid to ±1 g. For example, if

you are asked to add 23 mL of water, add between 22 mL and 24 mL. Which metals in each of the following sets will have equal density? *20.2 g gold placed in 21.6 mL of water and 12.0 g copper placed in 21.6 mL of water. *20.2 g silver placed in 21.6 mL of water and 12.0 g silver placed in 21.6 mL of water. *15.2 g copper placed in 21.6 mL of water and 50.0 g copper placed in 23.4 mL of water. *15.4 g gold placed in 20.0 mL of water and 15.7 g silver placed in 20.0 mL of water. *20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water. *11.2 g gold placed in 21.6 mL of water and 14.9 g gold placed in 23.4 mL of water.
Chemistry
2 answers:
WARRIOR [948]3 years ago
6 0

Answer:

20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water

Explanation:

Since the density formula is mass divided volume, you can calculate the density of each of the components of the group and see which of all the groups are equal

In the group

density Ag=20.2 g silver/21.6ml H2O=0.9352g/ml

density Cu=20.2 g copper/21.6ml H2O=0.9352 g/ml

KengaRu [80]3 years ago
5 0

<u>Answer:</u> The correct answer is 20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water

<u>Explanation:</u>

Density of a substance is defined as the ratio of its mass and volume. The chemical equation representing density of a substance is:  

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

Density is considered as an intensive property. Intensive property is the property that does not depend on the amount of substance. It remains same.

If the masses and volume of different substances are same, they will have same density.

For 20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water:

Density of silver = \frac{20.2g}{21.6mL}=0.935g/mL

Density of copper = \frac{20.2g}{21.6mL}=0.935g/mL

Hence, the correct answer is 20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water

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