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3 years ago

Can someone reword the two things in the boxes please?

Mathematics

1 answer:

Amanda [17]3 years ago

3 0

Answer:

1: The domain solely consists of whole numbers due to the fact that the child is only receiving the 25 cents at the end of each day. Therefore, no partial value is in the area of this function.

2: This outputs to this function are multiples of 0.25 beginning with 2.00. For instance, 2.00, 2.25, 2.50, 2.75, etc. Thus, an output of value 3.10 will in no way be accomplished through any enter in the domain.

Hope this helps, I've never been too good at this subject.

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For questions 4–5, simplify the expression.

Alex17521 [72]

1. $\mathrm{Group\:like\:terms} \ \textgreater \ 24h-10h+3d+8d$

$\mathrm{Add\:similar\:elements:}\:24h-10h=14h \ \textgreater \ 14h+3d+8d$

$\mathrm{Add\:similar\:elements:}\:3d+8d=11d \ \textgreater \ 14h+11d$

2. $\mathrm{Group\:like\:terms} \ \textgreater \ 12s+4s-2+4$

$\mathrm{Add\:similar\:elements:}\:12s+4s=16s \ \textgreater \ 16s-2+4$

$\mathrm{Add/Subtract\:the\:numbers:}\:-2+4=2 \ \textgreater \ 16s+2$

Hope this helps!

4 0

3 years ago

Sunnydale elementary school is having its annual read-a-thon.the third grader have read 573 books so far.their goal is to read m

Vera_Pavlovna [14]

900-573=327 To reach their goal the least amount of books they need to read is 327

5 0

3 years ago

Which relation is a function? PLEASE HELP

Georgia [21]

Answer:

Step-by-step explanation:

for the relation to be a function then each value of x in the domain must map to exactly one unique value of y in the range

this is the case for A

in B : 3 → 2 and 3 → 8 ← not a function

in C : - 2 → 5 and - 2 → 7 ← not a function

in D : 2 → 2 and 2 → 3 and 3 → 3 and 3 → 2 ← not a function

4 0

2 years ago

Read 2 more answers

Am I right for number 3

Kazeer [188]

Answer:

Yes

Step-by-step explanation:

Great job on your work! Hope you get a good grade! :)

4 0

4 years ago

Read 2 more answers

The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos

xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

Let X = annual salaries in the metropolitan Boston area

SO, X ~ Normal( $\mu=$50,542,\sigma^{2} = $4,246^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma }$ ~ N(0,1)

where, $\mu$ = average annual salary in the Boston area = $50,542

$\sigma$ = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

P(X > $57,000) = P( $\frac{X-\mu}{\sigma }$ > $\frac{57,000-50,542}{4,246 }$ ) = P(Z > 1.52) = 1 - P(Z $\leq$ 1.52)

= 1 - 0.93574 = 0.0643

The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

P(X < $46,000) = P( $\frac{X-\mu}{\sigma }$ < $\frac{46,000-50,542}{4,246 }$ ) = P(Z < -1.07) = 1 - P(Z $\leq$ 1.07)

= 1 - 0.85769 = 0.1423

The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

P(X > $40,000) = P( $\frac{X-\mu}{\sigma }$ > $\frac{40,000-50,542}{4,246 }$ ) = P(Z > -2.48) = P(Z < 2.48)

= 1 - 0.99343 = 0.0066

The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

P($45,000 < X < $54,000) = P(X < $54,000) - P(X $\leq$ $45,000)

P(X < $54,000) = P( $\frac{X-\mu}{\sigma }$ < $\frac{54,000-50,542}{4,246 }$ ) = P(Z < 0.81) = 0.79103

P(X $\leq$ $45,000) = P( $\frac{X-\mu}{\sigma }$ $\leq$ $\frac{45,000-50,542}{4,246 }$ ) = P(Z $\leq$ -1.31) = 1 - P(Z < 1.31)

= 1 - 0.90490 = 0.0951

The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = 0.6959

3 0

3 years ago