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slamgirl [31]
2 years ago
13

Atomic weight and atomic number of an element is 35 and 17 respectively​

Chemistry
1 answer:
mart [117]2 years ago
7 0
Chlorine.

Chlorine is the 17th element and has a mass of 35.
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What is convection cell​
kkurt [141]

Answer:

Explanation:

a self-contained convective zone in a fluid in which upward motion of warmer fluid in the center is balanced by downward motion of cooler fluid at the periphery.

3 0
3 years ago
Please help!!! Is it balanced or unbalanced?
Black_prince [1.1K]

Hey there!

I believe the answer you are looking for is Unbalanced!

If I am incorrect I am very sorry and would love any feedback.

Have a nice day, and Happy Halloween!

6 0
3 years ago
(a) 4.64 x 1024 atoms Bi into grams
nexus9112 [7]

Answer:

1610.7 g is the weigh for 4.64×10²⁴ atoms of Bi

Explanation:

Let's do the required conversions:

1 mol of atoms has 6.02×10²³ atoms

Bi → 1 mol of bismuth weighs 208.98 grams

Let's do the rules of three:

6.02×10²³ atoms are the amount of 1 mol of Bi

4.64×10²⁴ atoms are contained in (4.64×10²⁴ . 1) /6.02×10²³ = 7.71 moles

1 mol of Bi weighs 208.98 g

7.71 moles of Bi must weigh (7.71 . 208.98 ) /1 = 1610.7 g

5 0
3 years ago
Consider the reaction below. If you start with 4.00 moles of C3H8 (propane) and 4.00 moles of O2 , how many moles of propane wou
fgiga [73]

Answer:

0.800 mol

Explanation:

We have the amounts of two reactants, so this is a limiting reactant problem.  

We know that we will need a balanced equation with moles of the compounds involved.  

Step 1. <em>Gather all the information</em> in one place.

            C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol:  4.00    4.00

===============

Step 2. Identify the <em>limiting reactant </em>

Calculate the <em>moles of CO₂</em> we can obtain from each reactant.  

<em>From C₃H₈:</em>

The molar ratio of CO₂: C₃H₈ is 3:1

Moles of CO₂ = 4.00 × 3/1

Moles of CO₂ = 12.0 mol CO₂

<em>From O₂</em>:

The molar ratio of CO₂: O₂ is 3:5.

Moles of CO₂ = 4.00 × ⅗

Moles of CO₂ = 2.40 mol CO₂

O₂ is the limiting reactant because it gives the smaller amount of CO₂.

==============

Step 3. Calculate the <em>moles of C₃H₈ consumed</em>.

The molar ratio of C₃H₈:O₂ is 1:5.

Moles of C₃H₈ = 4.00 × ⅕

Moles of C₃H₈ = 0.800 mol C₃H₈

7 0
3 years ago
65. Write an equation for the combustion of octane.
siniylev [52]

Answer:

2C8H18+25O2→16CO2+18H2O.



4 0
2 years ago
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