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daser333 [38]
3 years ago
9

How much energy is used when a 110kw appliance is used for 3 hours

Physics
1 answer:
Bogdan [553]3 years ago
6 0
We could take the easy way out and just say

(110 kW) x (3 hours) = 330 kilowatt hours .

But that's cheap, and hardly worth even 5 points.
If we want to talk energy, let's use the actual scientific unit of energy.
________________________________________________

" 110 kw " means 110,000 watts = 110,000 joules/second .

(3 hours) x (3600 sec/hour) = 10,800 seconds.

(110,000 joules/second) x (10,800 seconds) = 1.188 x 10⁹ Joules

 That's

==>  1,188,000,000 joules

==>  1,188,000 kilojoules

==>  1,188 megajoules

==>  1.188 gigajoules

Atsa nawfulotta energy ! 
It goes back to that "110 kw appliance" that we started with. 
That's no common ordinary household appliance.  110 kw is something like
147 horsepower.  In order to bring 110 kw into your house, you'd need to
take 458 Amperes through the 240-volt line from the pole.  Most houses
are limited to 100 or 200 Amperes, tops.  And the TRANSFORMER on
the pole, that supplies the whole neighborhood, is probably a 50 kw unit.  
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\\ \rm\longmapsto Momentum=Mass\times velocity

\\ \rm\longmapsto Mass=\dfrac{Momentum}{Velocity}

\\ \rm\longmapsto Mass=\dfrac{23.4}{2}

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4 0
3 years ago
A cylinder which is in a horizontal position contains an unknown noble gas at 4.63 × 104 Pa and is sealed with a massless piston
AleksandrR [38]

Answer:

The change in internal energy of the system is -17746.78 J

Explanation:

Given that,

Pressure P=4.63\times10^{4}\ Pa

Remove heat \Delta U= -1.95\times10^{4}\ J

Radius = 0.272 m

Distance d = 0.163 m

We need to calculate the internal energy

Using thermodynamics first equation

dU=Q-W...(I)

Where, dU = internal energy

Q = heat

W = work done

Put the value of W in equation (I)

dU=Q-PdV

Where, W = PdV

Put the value in the equation

dU=-1.95\times10^{4}-(4.63\times10^{4}\times3.14\times(0.272)^2\times(-0.163))

dU=-17746.78\ J

Hence, The change in internal energy of the system is -17746.78 J

3 0
4 years ago
The period of a sound wave coming from an instrument is 0. 002 seconds. What is the frequency of the sound? Hz.
Pie

The period is the time taken by the wave to complete an oscillation. The frequency of the given sound is 500 Hz.

<h2>Period:</h2>

It is the time taken by the wave to complete an oscillation. The frequency is inversely proportional to the time:

f = \dfrac 1T

Where,

f- frequency

T - period = 0.002 s

Put the value in the equation,

f = \dfrac 1{0.002}\\\\f = 500\rm \  Hz

Therefore, the frequency of the given sound is 500 Hz.

Learn more about Period:

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5 0
2 years ago
Xavier is roller skating at 14 km/h and tosses a set of keys forward on the ground at 8 km/h. The speed of the keys relative to
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Answer:

22 km/h

Explanation:

Given that,

Speed of Xavier, v = 14 km/h

He tosses a set of keys forward on the ground at 8 km/h, v' = 8 km/h

We need to find the speed of the keys relative to the ground. Let it is V.

As both Xavier and the keys are moving in same diretion. The relative speed wrt ground is given by :

V = v+v'

V= 14 + 8

V = 22 km/h

So, the speed of the keys relative to the ground is 22 km/h.

4 0
3 years ago
A<br> Н20= C=1 h=4 o=4<br> 2.<br> H3PO4 +<br> КОН<br> KзРО І
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Answer:

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