Cause limestone breaks down dirt and stone
Answer:
C) 4.24 x ![10^{-12}](https://tex.z-dn.net/?f=10%5E%7B-12%7D)
Explanation:
E = Δm![c^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D)
Δm = 0.0284 x 1.66 x
kg = 4.714x
kg
putting value in above equation
E = 4.714x
kg x (3x![10^{8}](https://tex.z-dn.net/?f=10%5E%7B8%7D)
= 4.24 x ![10^{-12}](https://tex.z-dn.net/?f=10%5E%7B-12%7D)
The mass of 254 mL of water is 254 g. Since the density of water is 1g/mL, we can simply multiply the density 1g/mL by 254 mL of water and get 254 g as our answer. Since mL is in the numerator and denominator, mL cancels out and we are left with g only.
Answer: The volume of the sample after the reaction takes place is 29.25 L.
Explanation:
The given reaction equation is as follows.
![OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)](https://tex.z-dn.net/?f=OF_%7B2%7D%28g%29%20%2B%20H_%7B2%7DO%28g%29%20%5Crightarrow%20O_%7B2%7D%28g%29%20%2B%202HF%28g%29)
So, moles of product formed are calculated as follows.
Hence, the given data is as follows.
= 0.17 mol,
= 0.255 mol
= 19.5 L, ![V_{2} = ?](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%20%3F)
As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.
![\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B1%7D%7D%7Bn_%7B1%7D%7D%20%3D%20%5Cfrac%7BV_%7B2%7D%7D%7Bn_%7B2%7D%7D)
Substitute the values into above formula as follows.
![\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B1%7D%7D%7Bn_%7B1%7D%7D%20%3D%20%5Cfrac%7BV_%7B2%7D%7D%7Bn_%7B2%7D%7D%5C%5C%5Cfrac%7B19.5%20L%7D%7B0.17%20mol%7D%20%3D%20%5Cfrac%7BV_%7B2%7D%7D%7B0.255%20mol%7D%5C%5CV_%7B2%7D%20%3D%20%5Cfrac%7B19.5%20L%20%5Ctimes%200.255%20mol%7D%7B0.17%20mol%7D%5C%5C%3D%20%5Cfrac%7B4.9725%7D%7B0.17%7D%20L%5C%5C%3D%2029.25%20L)
Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.
<h3><u>Full Question:</u></h3>
The following compound has been found effective in treating pain and inflammation (J. Med. Chem. 2007, 4222). Which sequence correctly ranks each carbonyl group in order of increasing reactivity toward nucleophilic addition?
A) 1 < 2 < 3
B) 2 < 3 < 1
C) 3 < 1 < 2
D) 1 < 3 < 2
<h3><u>Answer: </u></h3>
The rate of nucleophilic attack of carbonyl compounds is 2<3 <1.
Option B
<h3><u>Explanation. </u></h3>
Nucleophilic attack is explained as the attack of an electron rich radical to a carbonyl compound like aldehyde or a ketone. A nucleophile has a high electron density, so it searches for a electropositive atom where it can donate a portion of its electron density and become stable.
A carbonyl compound is a
hybridized carbon atom with a double bonded oxygen atom in it. The oxygen atom pulls a huge portion of electron density from carbon being very electropositive.
In a ketone, there are two factors that make it less likely to undergo a nucleophilic attack than aldehyde. Firstly, the steric hindrance of two carbon groups being attached with the carbonyl carbon makes it harder for the nucleophile to approach. Secondly, the electron push by the carbon groups attached makes the carbonyl carbon a bit less electropositive than the aldehyde one. So aldehydes are more reactive towards a nucleophilic addition reaction.