Answer:
191 °C
Explanation:
We'll begin by calculating the number of mole in 88.0 g of Ne. This can be obtained as follow;
Mass of Ne = 88.0 g
Molar mass of Ne = 20 g/mol
Mole of Ne =?
Mole = mass /molar mass
Mole of Ne = 88 / 20
Mole of Ne = 4.4 moles
Next, we shall determine the temperature. This can be obtained as follow:
Mole of Ne = 4.4 moles
Pressure (P) = 350 KPa
Volume (V) = 48.5 L
Gas constant (R) = 8.314 KPa.L/Kmol
Temperature (T) =?
PV = nRT
350 × 48.5 = 4.4 × 8.314 × T
16975 = 36.5816 × T
Divide both side by 36.5816
T = 16975 / 36.5816
T = 464 K
Finally, we shall convert 464 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T(K) = 464 K
T(°C) = 464 – 273
T(°C) = 191 °C
Thus, the temperature is 191 °C
The elements that form anions will have the electronic configuration similar to the noble gas that is in their period and those that form cations will have a configuration similar to that of the noble gas in the previous period.
He: Be
Ne: F, Al
Ar: Ca, P
Kr: Rb, Se
They use fans and air conditioning in the summer because its hot, which means they use energy and in the winter, there is no need because its cold so less energy.
I believe it’s c since it’s 2.5 cups of flour for each butter
Answer:
4 Ag⁺ + 2 H₂O + BrO⁻ → 4 Ag + BrO₃⁻ + 4 H⁺
Explanation:
In order to balance a redox reaction, we will use the ion-electron method.
Step 1: Identify both half-reactions
Reduction: Ag⁺ → Ag
Oxidation: BrO⁻ → BrO₃⁻
Step 2: Perform the mass balance adding H⁺ and H₂O where necessary
Ag⁺ → Ag
2 H₂O + BrO⁻ → BrO₃⁻ + 4 H⁺
Step 3: Perform the electrical balance adding electrons where necessary
1 e⁻ + Ag⁺ → Ag
2 H₂O + BrO⁻ → BrO₃⁻ + 4 H⁺ + 4 e⁻
Step 4: Multiply both half-reactions by numbers that secure that the number of electrons gained and lost are equal
4 × (1 e⁻ + Ag⁺ → Ag)
1 × (2 H₂O + BrO⁻ → BrO₃⁻ + 4 H⁺ + 4 e⁻)
Step 5: Add both half-reactions
4 e⁻ + 4 Ag⁺ + 2 H₂O + BrO⁻ → 4 Ag + BrO₃⁻ + 4 H⁺ + 4 e⁻
4 Ag⁺ + 2 H₂O + BrO⁻ → 4 Ag + BrO₃⁻ + 4 H⁺
