Volume of Hydrogen V1 = 351mL
Temperature T1 = 20 = 20 + 273 = 293 K
Temperature T2 = 38 = 38 + 273 = 311 K
We have V1 x T2 = V2 x T1
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56
Volume at 38 C = 373 ml
Answer:
C. 30 kJ
Explanation:
Hello there!
In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

Therefore, the answer is C. 30 kJ
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Answer:
c
Explanation:
plants decrease the levels of carbon dioxide in the atmosphere due to the process of photosynthesis
Answer:
1 atm
Explanation:
Step 1: Write the balanced equation
NH₄OH(aq) ⇒ H₂O(l) + NH₃(g)
Step 2: Calculate the moles corresponding to 8 g of NH₄OH
The molar mass of NH₄OH is 35.04 g/mol.
8 g × 1 mol/35.04 g = 0.2 mol
Step 3: Calculate the moles of NH₃ formed from 0.2 moles of NH₄OH
The molar ratio of NH₄OH to NH₃ is 1:1. The moles of NH₃ formed are 1/1 × 0.2 mol = 0.2 mol
Step 4: Calculate the pressure of 0.2 moles of NH₃ in a container of 5.00 L at 25 °C (298 K)
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T / V
P = 0.2 mol × 0.0821 atm.L/mol.K × 298 K / 5.00 L
P = 1 atm