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Murljashka [212]
3 years ago
11

Jessie deposited 920 into a savings account that pays a simply annual interest rate of 1.79% how much interest will he earn afte

r 5 years?
Mathematics
1 answer:
N76 [4]3 years ago
8 0
After 5 years =4616.468
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Two parallel lines are crossed by a transversal. What is the value of h? h = 60 h = 80 h = 100 h = 120
lisabon 2012 [21]
I added the diagram of the question.

<u><em>Answer:</em></u>
h = 60°

<u><em>Explanation:</em></u>
We are given that lines k and l are parallel lines.
This means that angles 120° and h are <u>supplementary angles</u>.
This means that their measures <u>add up to 180°</u>

<u>Therefore:</u>
180° = 120° + h
h = 180° - 120°
h = 60°

Hope this helps :)

8 0
3 years ago
Read 2 more answers
In triangle abc, cos A= -0.6. Find A and Tan A
Tresset [83]

Answer:

Part 1) A=126.87^o

Part 2) tan(A)=-\frac{4}{3}

Step-by-step explanation:

we have

cos(A)=-0.6

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive

The angle A lie on the II Quadrant

step 1

Find the measure of angle A

cos(A)=-0.6

using a calculator

A=cos^{-1}(-0.6)=126.87^o

step 2

Find the sin(A)

we know that

sin^2(A)+cos^2(A)=1

substitute the value of cos(A)

sin^2(A)+(-0.6)^2=1

sin^2(A)=1-0.36

sin^2(A)=0.64

sin(A)=0.8

step 3

Find tan(A)

we know that

tan(A)=\frac{sin(A)}{cos(A)}

substitute the values

tan(A)=\frac{0.8}{-0.6}

Simplify

tan(A)=-\frac{4}{3}

5 0
3 years ago
Does anyone know why x is normally used for an unknown number?
jeka94

Then you are able to substitute in X and it can have a infinite number of values catered to the question.

7 0
3 years ago
PLEASE HELP ME!!!! I NEED THIS QUICKLY!!
Sergio [31]

Answer:

i79

Step-by-step explanation:

7 0
3 years ago
Find lim x-&gt;2 for f(x)=
TiliK225 [7]

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

8 0
2 years ago
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