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a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2
<span>= 2.40 x 10-3 N
b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
Answer:
Explanation:
The diagram has a fairly simple explanation. In the top diagram, the space between the particle is increasing. That means that acceleration is increasing. The bottom diagram shows just the opposite. The particle starts off making large "distances" between where the particle is recorded and then the distances between recordings lessens and the particle is slowing down.
Rule: the greater the "distance" between dot positions, the greater the acceleration, because the speed is large.
Top diagram: increasing distance between dots = larger speed. The distance becomes greater as the particle moves to the right.
Bottom diagram: starts off large and decreases as we move from left to right = - acceleration.
<span>La segunda ley de Newton se conoce como la ley del movimiento de las partículas. <span>Dice que si sobre un cuerpo de masa en una sola fuerza Féliz que recibe una descarga de tal que F = ma.
</span></span>Y la primera <span>establece que un objeto permanecerá en reposo o con movimiento unifome rectilíneo al menos que sobre él actúe una fuerza externa.
Espero q te sirva :)</span>
The acceleration of gravity on Earth is about 9.8 m/s².
That means that if air resistance is neglected, a falling body
smoothly gains 9.8 m/s of downward speed each second.
If our intrepid chutist lightly stepped out of the plane or was
gently pushed, so that his initial downward speed was zero
and grew by 9.8 m/s every second, then it took him ...
(55) / (9.8) = 5.6 seconds
to reach that particular downward speed.
Answer:
5501 kg/m^3
Explanation:
The value of g at the Earth's surface is

where G is the gravitational constant
M is the Earth's mass
is the Earth's radius
Solving the formula for M, we find the value of the Earth's mass:

The Earth's volume is (approximating the Earth to a perfect sphere)

So, the average density of the Earth is
