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4 years ago

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Chemistry

1 answer:

laiz [17]4 years ago

6 0

Option A is correct answer.

According to octet rule, atoms have tendency to lose, gain and share electrons to complete its octet i.e. eight valence electrons are surrounded to the atom.

Since, sulphur contains six valence electrons and two chlorine atoms are present in the reaction having seven valence electrons. Thus, to complete their octet, chlorine shares a pair of electrons with the sulphur atom.

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How many Liters of 0.50M HCl are needed to neutralize 0.050L of 0.101M Ba(OH)2?

Aleksandr-060686 [28]

Answer:

$V_{HCl}=5.05x10^{-3}L$

Explanation:

Hello,

In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

$2*n_{HCl}=n_{Ba(OH)_2}$

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

$2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L$

Besr regards.

8 0

3 years ago

Read 2 more answers

When coal is burned, the sulfur present in coal is converted to sulfur dioxide (SO2), which is responsible for the acid rain phe

solmaris [256]

Answer : The volume of $SO_2$ gas is, $2.75\times 10^6mL$

Explanation : Given,

Mass of S = 4.10 kg = 4100 g (1 kg = 1000 g)

Molar mass of S = 32 g/mol

First we have to calculate the moles of S.

$\text{Moles of }S=\frac{\text{Given mass }S}{\text{Molar mass }S}=\frac{4100g}{32g/mol}=128.125mol$

Now we have to calculate the moles of $SO_2$

The balanced chemical reaction is:

$S(s)+O_2(g)\rightarrow SO_2(g)$

From the balanced reaction, we conclude that

As, 1 mole of $S$ react to give 1 mole of $SO_2$

So, 128.125 mole of $S$ react to give 128.125 mole of $SO_2$

Now we have to calculate the volume of $SO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = Pressure of $SO_2$ gas = 1.16 atm

V = Volume of $SO_2$ gas = ?

n = number of moles $SO_2$ = 128.125 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $SO_2$ gas = $30^oC=273+30=303K$

Putting values in above equation, we get:

$1.16atm\times V=128.125mole\times (0.0821L.atm/mol.K)\times 303K$

$V=2747.65L=2.75\times 10^6mL$ (1 L = 1000 mL)

Therefore, the volume of $SO_2$ gas is, $2.75\times 10^6mL$

4 0

3 years ago

What is the pow of a<br> 2.1 x 10-6 M OH-solution?

Andreyy89

Explanation:

pOH = ? (Data) molarity = 2.1 x 10 -6 M (formula) pOH = log /[OH] substitution pOH = -log [2.1 x 10-6] pOH = 5.7 and pH =14 - pOH ph -14 -5.7 pH = 8.3

8 0

3 years ago

Dmitrij [34]

C I’m pretty sure that is the answer

5 0

2 years ago

Which statement describes a chemical property that many elements might share?

nata0808 [166]

ANSWER:

I think its B.

6 0

4 years ago