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postnew [5]
3 years ago
14

1. A bacterium that can use NO3 - as a terminal electron acceptor is found to contain sulfur granules. This cell . . . A. reduce

s sulfur B. oxidizes NO3 - C. is a nitrifying bacterium D. is a chemotroph E. cannot produce a PMF directly
Chemistry
1 answer:
Colt1911 [192]3 years ago
5 0

Answer: Option D

Explanation:

Chemotrophs can be defined as the organism which has the ability to get energy by the oxidation of electron donors present in the nearby environments.

These molecules in the environment can be organic or inorganic.These bacteria are usually called as thiobacillus denitrificans.

These bacteria reduce the nitrate into nitrite and the energy source for these bacteria is thiosulfate(sulfur).

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If you repeat an experiment and the result are very different from the result you got the first time the next step would be to w
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(HELP) how can you make the metal chair less cold when you sit on it?
soldi70 [24.7K]

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Which statement is true for a solution when its concentration of hydroxide ions increases? It becomes more acidic. It becomes le
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Its pH value increases.

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Read 2 more answers
Determine whether a precipitate will form when 0.96g of Na2CO3 is combined with 0.20g BaBr2 in a 10 L solution.
Mashcka [7]

Answer:

Qsp > Ksp, BaCO3 will precipitate

Explanation:

The equation of the reaction is;

Na2CO3 + BaBr2 -------> 2NaBr + BaCO3

Since BaCO3 may form a precipitate we can determine the Qsp of the system.

Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles

concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M

Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles

concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M

Hence;

[Ba^2+] = 6.7 * 10^-5 M

[CO3^2-] = 9.1 * 10^-4 M

Qsp = [6.7 * 10^-5] [9.1 * 10^-4]

Qsp = 6.1 * 10^-8

But, Ksp for BaCO3 is 5.1*10^-9.

Since Qsp > Ksp, BaCO3 will precipitate

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3 years ago
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