Answer:
The potential difference between the plates is 596.2 volts.
Explanation:
Given that,
Capacitance
Charge
Separation of plates = 0.313 mm
We need to calculate the potential difference between the plates
Using formula of potential difference
Where, Q = charge
C = capacitance
Put the value into the formula
Hence,The potential difference between the plates is 596.2 volts.
An element which is highly conductive, highly reactive, soft, and lustrous is most likely an alkali metal.
Alkali metals are in group 1 of the Periodic table which means that they have only a single valence electron.
This causes them to be soft and highly reactive because:
Examples of alkali electrons include:
In conclusion therefore, alkali metals are highly reactive and soft and so the element described above is most likely an alkali metal.
<em>Find out more at brainly.com/question/18722874.</em>
