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natka813 [3]
3 years ago
5

Which of the following equations correctly describes how to calculate net income? a. net income = (cost of goods sold) - (net sa

les) - (operating expenses) b. net income = (operating expenses) - (cost of goods sold) - (net sales) c. net income = (operating expenses) + (cost of goods sold) - (net sales) d. net income = (net sales) - (cost of goods sold) - (operating expenses) Please select the best answer from the choices provided A B C D Mark this and return
Chemistry
1 answer:
charle [14.2K]3 years ago
4 0

Answer:

The answer is D. net income= (net sales) - (cost of goods sold)- (operating expenses).

Explanation:

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Black holes….. universe……. radiation……. time
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2 years ago
Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where need
gregori [183]

Answer:

Explanation:

Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical.

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Which reaction illustrates the conservation of matter during a redox reaction
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<span>This question is simple, answers are D and C respectively</span>
6 0
3 years ago
Consider a sample of 11.2 g of ice initially at 0.0 C. How much energy in kilojoules is required to melt the ice and warm it to
oksian1 [2.3K]

Answer:

1034.88J

Explanation:

Given that:

mass (m) = 11.2 g, initial temperature = 0°C, final temperature = 22°C, the specific heat capacity of water (C) = 4.2 J/g°C

Temperature difference (ΔT) = final temperature - initial temperature = 22 - 0 = 22°C

The quantity of heat (Q) required to melt the ice can be calculated from the equation:

Q = mCΔT

Q = 11.2 g × 4.2 J/g°C × 22°C

Q = 1034.88J

5 0
3 years ago
How many grams of potassium iodine, kl,must be added to 500.0 grams of water to produce a 6.00% solution ?
GuDViN [60]

Answer:

grams KI needed = 31.9 grams

Explanation:

? g KI + 500 g water => 6.0% KI solution

let x = grams KI needed.

Percent = part/total x 100% = (x/x+500)·100% = 6.0%

Solve for 'x' ...

x / x + 500 = 6/100 = 0.06 => x = 0.06(x + 500) => x = 0.06x + 30

x - 0.06x = 30 => 0.94x = 30 => x = 30/0.94 = 31.9 gms KI needed.  

6 0
3 years ago
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