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2 years ago

What is a non example of tendon?

Chemistry

1 answer:

Maurinko [17]2 years ago

4 0

Answer:

so the definition of it like the non example thing would be a flexible but elastic cord of strong flubber containing tissue and muscle to a bone the Hampshire of

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What is the mass of 0.5 moles of carbon tetrafluoride, CF4?

VashaNatasha [74]

Answer:

44 g

Explanation:

The formula for the number of moles (n) is equal to $n=\frac{mass}{molecular weight}$ .

Since we need to find the mass, we derive it from the formula of the number of moles and we get that mass = n x molecular weight .

The molecular weight of $CF_{4}$ = 12 g/mol (from the carbon) + 19x4 g/mol (from the 4 fluorine atoms)= 88 g/mol

We plug in the numbers in the derived formula for the mass and we get :

mass = n x molecular weight = 0.5 mol x 88 g/mol = 44 g

4 0

2 years ago

Read 2 more answers

The denser and thicker a liquid is, the higher the buoyancy of an object is. In other words, if the density of a certain fluid i

Marta_Voda [28]

Answer:

Yes this is true.

Explanation:

3 0

2 years ago

Which of the following is a pure substance

sergij07 [2.7K]

What is the following

8 0

3 years ago

What is the name of the compound that has the formula Li2SO3?

Oduvanchick [21]

The answer is A lithium sulfite

7 0

3 years ago

Read 2 more answers

Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o

jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

Step 1: The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

Step 2: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

Step 3: Calculate moles of glucose

Moles glucose = Mass glucose / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

Step 4: Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

Step 5: Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

Step 6: Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0

3 years ago