All categories

3 years ago

What is a non example of tendon?

Chemistry

1 answer:

Maurinko [17]3 years ago

4 0

Answer:

so the definition of it like the non example thing would be a flexible but elastic cord of strong flubber containing tissue and muscle to a bone the Hampshire of

You might be interested in

What is the molar mass of glucose, C3H603?

ziro4ka [17]

Answer:

The mass percentage of carbon can be found easily using the molar mass of C6H12O6, 180.1559 g/mol. We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass. C6H12O6 = CO2 + C3H6O3 + CH3OCH3 Take fructose for example. Compound.

Explanation: I looked it up

4 0

2 years ago

When a hurricane approaches land, people living directly on the

Tatiana [17]

Answer:

True

Explanation:

When a hurricane is dangerous enough that authorities say to evacuate, you should for your own safety.

3 0

2 years ago

A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a

Nata [24]

Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

The mass of CuSO₄ anhydrous is:

23,403g - 22,652g = 0,751g.

mass of crucible+lid+CuSO₄ - mass of crucible+lid

As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g × $\frac{1mol}{159,609g}$ = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

mass of crucible+lid+CuSO₄hydrate - CuSO₄ - mass of crucible+lid

As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g × $\frac{1mol}{18,02g}$ = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have <em>5,5668 moles of water per mole of CuSO₄.</em>

I hope it helps!

5 0

3 years ago

The complete orbital notation diagram of an atom is shown.

Yuki888 [10]

Answer:

Explanation:

From the description provided by the statement of the problem, we can easily solve for the values of the angular momentum quantum number.

Let us represent the atom as J:

In atom J, we have five sub-orbitals in which there 9 electrons. From the designation used to represent sublevels, we can write the notation as below:

J = 10 electrons = 1s² 2s² 2p⁵

The s-sublevel can only contain 2 electrons

p-sublevel can contain 6 electrons but we have just 5 electrons in there.

Now, to find the angular momentum quantum number, we need to understand what this quantum number denotes.

This quantum number is also known as azimuthal or secondary quantum number. It gives the shape of the orbitals in subshells accomodating electrons. This quantum number is designated by (l).

l (n-1) name of orbital shape of orbital

0 s spherical

1 p dumb-bell

2 d double dumb-bell

3 f complex

J = 1s² 2s² 2p⁵

where 1 and 2 coefficients are the principal quantum numbers(n).

s and p are the shape of the orbitals

For 1s², the l vaue is 0 because the electron is in the s orbital

2s² the l value is 0, 1 and the electron can be in the s or p orbitals

2p⁵ the l value is 0, 1 and the electrons can be in the s or p orbitals

The quantum number gives the shape of the orbital.

8 0

3 years ago

Fe + O2 —> Fe2O3<br><br> can someone pls help me balance this??

zimovet [89]

Answer:

4Fe + 3O2 → 2Fe2O3

5 0

2 years ago