James started his homework at 4:15pm. He spent half an hour on maths and 45minutes on English.
2 answers:
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Answer:
and
Step-by-step explanation:
We are asked that what are the zeros of the quadratic function f(x) = 6x² +12x -7.
So, we have to find the roots of the equation, f(x) = 6x² +12x -7 =0 ...... (1)
Since the quadratic function can not be factorized, so we have to apply Sridhar Acharya's formula.
This formula gives if, ax² +bx +c =0, the the two roots of the equation are
Therefore, in our case 'a' being 6, 'b' being 12 and 'c' being -7, the two roots of the equation (1) will be
=
= and
Hence, x=
and x=
(Answer)
12w-27 = -34+14w
We need to keep variables on one side and constant on other side . Here variables are 12w and 14w and constants are -27 and -34 .
So we need to move -34 to left side and 12 w to right side . And for that, we need to add 34 to both sides and subtract 12 w to both sides.
12w-27+34-12w=-34+14w+34-12w
7= 2w
Now we need to get rid of 2. So we divide both sides by 2 , and on doing that, we will get