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n200080 [17]
2 years ago
15

A circuit has a voltage drop of 60.0 V across a 120.0 resistor that carries a current of 0.500 A. What is the power conducted by

the resistor? Use P = VI.
A.
7200 W

B.
60.0 W

C.
2.00 W

D.
30.0 W
Physics
1 answer:
olasank [31]2 years ago
3 0

Answer:

Power, P = 30 W

Explanation:

We have,

Voltage drop of a circuit is 60 V

Resistance of the resistor is 120 ohms

Current across the circuit is 0.5 A

It is required to find the power conducted by the resistor. Power conducted by a resistor is given by :

P=VI

V and I are voltage and current

P=60\times 0.5\\\\P=30\ W

So, the power conducted by the resistor is 30 watts.

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How do you calculate the fundamental frequency of a pipe?
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What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 20.0 km/h?
Tanya [424]

Answer:

The minimum coefficient of friction is 0.22

Explanation:

Suppose If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve.

We need to calculate the ideal speed to take a 85 m radius curve banked at 15°.

Given that,

Radius = 85 m

Angle = 15°

Speed = 20 km/h

We need to calculate the ideal speed

Using formula of speed

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v=\sqrt{85\times9.8\tan15}

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We need to calculate the minimum coefficient of friction

Using formula for coefficient of friction

v^2=\dfrac{rg(\sin\theta-\mu\cos\theta)}{\mu\sin\theta+\cos\theta}

Put the value into the formula

(5.55)^2=\dfrac{85\times9.8(\sin15-\mu\cos15)}{\mu\sin15+\cos15}

\dfrac{30.8025}{85\times9.8}=\dfrac{0.2588-\mu0.966}{\mu0.2588+0.966}

0.9754462\ mu-0.223541=0

\mu=\dfrac{0.223541}{0.9754462}

\mu=0.22

Hence, The minimum coefficient of friction is 0.22

3 0
2 years ago
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