Question

A balloon is filled with air to a capacity of 6 L while underwater at a depth where the water pressure is 210 kPA. To what volume would this balloon expand if it suddenly rose to the surface.

Answer 1

Answer: Thus the balloon will expand to 12.5 L if it suddenly rose to the surface.

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=210kPa\\V_1=6L\\P_2=101kPa\\V_2=?$

Putting values in above equation, we get:

$210\times 6=101\times V_2\\\\V_2=12.5L$

Thus the balloon will expand to 12.5 L if it suddenly rose to the surface.