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lozanna [386]
2 years ago
12

A moonshiner makes the error of filling a glass jar to the brim and capping it tightly. The moonshine expands more than the glas

s when it warms up, in such a way that the volume increases by 0.6% (that is, ΔV/V0 = 6 ✕ 10-3) relative to the space available. Calculate the force exerted by the moonshine per square centimeter if the bulk modulus is 2.1 ✕ 109 N/m2, assuming the jar does not break.

Physics
1 answer:
iogann1982 [59]2 years ago
8 0

The force exerted per square centimeter is 126 N/cm².

<h3>What is pressure?</h3>

Pressure is the force acting per unit area.

  • Pressure = force/area

Based on the data given:

volume increase, ΔV/V0 = 6 * 10⁻³

Bulk Modulus, B = 2.1 * 10⁹ N/m²

Bulk modulus B of a material is ratio of change in pressure and change in volume as given below:

  • B = ΔP/ [(ΔV/V)]

Solving for ΔP;

ΔP = B * [(ΔV/V)]

ΔP = (2.1 * 10⁹ N/m²) * (6 * 10⁻³)

ΔP = 1.26 * 10⁶ N/m²

Converting to per square centimeter

ΔP = (1.26 * 10⁶ N/m²)/10⁴

ΔP = 126 N/cm²

In conclusion, the force exerted per square centimeter is a measure of the pressure.

Learn more about pressure at: brainly.com/question/15428847

#SPJ1

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<h3>Ion beams and Electrochemical are two examples of direct current electricity.</h3>
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How many calories are needed to raise the temperature of 2g of water 3 C?
olga nikolaevna [1]

Answer:

The number of calories needed is 6c.

Explanation:

The amount of energy Q needed to raise the temperature \Delta T of water of mass m is

Q = mC\Delta T

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Putting in numbers into equation (1), we get:

Q = (2g)(1)(3^oC )\\

\boxed{Q = 6\:cal }

which is the number of calories needed.

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Answer:

Q_T=63313.5\ J

Explanation:

Given:

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  • initial temperature of steam vapour, T_v=100^{\circ}C
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  • mass of steam, m=25\ g
  • specific heat of water, c=4190\ J.kg^{-1}.K^{-1}=4.19\ J.g^{-1}.K^{-1}
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<em>Assuming that no heat is lost in the surrounding.</em>

<u>We know:</u>

Q=m.c.\Delta T

<u>Now the total heat given by the steam to form water at the given conditions:</u>

Q_T=Q_{Lv}+Q_w ..............................(1)

where:

Q_{Lv}= latent heat given out by vapour to form water of 100°C

Q_w= heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

Q_T=m(L+c.\Delta T)

Q_T=25(2256+4.19\times 66)

Q_T=63313.5\ J

is the heat transferred to the skin.

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Molar mass of C₂H₆O₂ is = (2×12) +(6×1) + (216) = 62g/mol
Now that antifreeze by mass is 50%, then there is 1kg of ethylene glycol which is present in 1kg of water.
ΔTf = Kf×m
ΔTf = depression in the freezing point.
= freezing point of water freezing point of the solution
= O°c - Tf
= -Tf
Kf = depression in freezing constant of water = 1.86°C/m
M is the molarity of the solution.
=(mass/molar mass) mass of solvent in kg
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If we plug the value we get 
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