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4 years ago

Give a combination of four quantum numbers that could be assigned to an electron occupying a 5p orbital.

Physics

1 answer:

Elden [556K]4 years ago

8 0

Answer:

n=5, l=1, m(l) = -1, m(s)= + 1/2

Explanation:

Quantum number are used to describe the position and spin of an electron inside an atom. There are four types of quantum number for describing an electron inside an atom. They are: the principal quantum number, spin quantum number, magnetic quantum number and angular momentum quantum number.

(1).PRINCIPAL QUANTUM NUMBER: denoted by n, and has possible values of n= 1,2,3,4,.... IN HERE, n= 5

(2).ANGULAR MOMENTUM QUANTUM NUMBER: it is denoted by l, and has possible values of l= 0,1,2,3,...,(n-1).

Our l here is one( that is, s-orbital=0, p-orbital=1, d-orbital= 3 and so on)

(3).MAGNETIC QUANTUM NUMBER: The magnetic quantum number, which is denoted by m subscribt l, specifies the exact orbital in which you can find the electron. It has values ranging from -l,...,-1,0,1,...,l.

Here, our value is -1 that is m(l)= -1

(4).SPIN QUANTUM NUMBER: describes the orientation of electrons. Electrons can only have two values here, either a positive one and the half(+1/2) that is the spin up electron or the negative one and half(-1/2) that is the spin down electron.

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A runner of mass 60.0kg runs around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its cent

Elenna [48]

Answer:

See explanation

Explanation:

In this exercise, we need to use the law of conservation of angular momentum which is:

I1*W1 + I2*W2 = (I1 + I2)*W2'

Where:

I: moment of innertia.

W: angular velocity

Now let's call 1 the runner and 2, the turntable. the system would be W2'.

The angular speed of the runner, we can calculate that with the following expression:

W = V/r

so:

W1 = 2.5 / 3.6 = 0.694 rad/s

The innertia is calculated with the expression:

I = m*r²

I = 60 * 3.6 = 216 kg.m²

I2 and W2 are provided in the exercise, so, replacing all the data in the conservation of angular momentum, let's solve for W2'

(216*0.694) + (-0.190*81) = (81 + 216)W2'

134.514 = 297W2'

W2' = 134.514 / 297

W2' = 0.453 rad/s

5 0

4 years ago

Two identical spheres, A and B, are placed 15 cm apart. The sphere A is charged to 5.0 μC and the sphere B is charged to –7.0 μC

Inga [223]

Answer:

a. F = 14 N

b. Since the spheres' charges have different signs, the force is attractive

Explanation:

Coulomb's Law

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

$\displaystyle F=k\cdot\frac{q_1q_2}{d^2}$

Where:

$k=9\cdot 10^9\ N.m^2/c^2$

q1, q2 = the objects' charge

d= The distance between the objects

The spheres A and B have charges of:

$q_1=5\cdot 10^{-6}\ c$

$q_2=7\cdot 10^{-6}\ c$

The distance is d=15 cm = 0.15 m.

a. The force is now calculated:

$\displaystyle F=9\cdot 10^9\cdot\frac{5\cdot 10^{-6}\cdot 7\cdot 10^{-6}}{0.15^2}$

$\displaystyle F=9\cdot 10^9\cdot\frac{35\cdot 10^{-12}}{0.0225}$

F = 14 N

b. The electrostatic force between charges is repulsive if they have like signs, the force between them is attractive if they have opposite signs.

Since the spheres' charges have different signs, the force is attractive

6 0

3 years ago

A competitive diver executes a double somersault with a twist from a platform. Her height above the water t seconds after leavin

GarryVolchara [31]

Answer:

One second

Explanation:

Her height above water as function of time after leaving the board is:

$h(t)=-16t^2 +0t+ 16$

When she enters the water the height above the board is zero so h(t)=0, using that on (1):

$0=-16t^2 +0t+ 16$

solving equation for t:

$16t^2=16$

$t^2=1$

$t=\sqrt{1}=1$ s

Mathematically there're in fact two possible values for t, -1 and 1 but because we're talking of time negative sign has no physical sense then we only use 1.

7 0

3 years ago

Two balls are thrown horizontally. Ball C is thrown with a force of 20 N, and ball D is thrown with a force of 40 N. Assuming al

vagabundo [1.1K]

Answer:

ball D will fall toward the ground at the same time as ball C

Explanation:

both balls experience the same downward (vertical) force of gravity as such they will both fall down at the same time, given that all other factors are equal.

although the ball were through with different forces,

those forces where in the horizontal direction but the force of gravity (downward force) will act on them equally to bring them down at the same time

6 0

3 years ago

A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T

solmaris [256]

Answer: Impulse is greater in the first case. So, option C is the correct option.

Explanation:

Case 1: Cart is travelling at 0.3 m/s and collide with an stationary object and after collision, cart rebound in opposite direction and another object remains in static condition.

Applying the conservation of linear momentum:

$m_{1} \times u_{1} + m_{2} \times u_{2} = m_{1} \times v_{1} + m_{2} \times v_{2}$

$m_{1} \times 0.3 + m_{2} \times 0 = m_{1} \times v_{1} + m_{2} \times 0$

Hence velocity of cart will rebound with the same velocity i.e. 0.3 m/s

Impulse is defined as the change in momentum

Impulse on the cart = $m_{1} \times v_{1} - m_{1} \times u_{1}$ = $m_{1} \times ((-3) - (3)) = m_{1} \times (-6)$ Kg m/s.

Case 2: Initially cart is travelling at 0.3 m/s and after collision it comes to rest.

So, change in momentum or Impulse = $m_{1} \times (0 - 3)$ = $-3 \times m_{1}$ Kg m/s.

Impulse is greater in the first case. So, option C is the correct option.

8 0

4 years ago

Read 2 more answers