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4 years ago

8

Figure this out please

2 answers:

rusak2 [61]4 years ago

7 0

Answer:

570 cm³

Step-by-step explanation:

Check the rule in your picture about Calculating the volume of a prism:

Volume = (2×15)×19

= 570

irina [24]4 years ago

6 0

<h3>Answer: 380 cubic cm</h3>

Explanation:

The front and back faces are trapezoids. Focus on one of the trapezoids.

I'll focus on the front face. It has parallel sides of b1 = 15 and b2 = 5. The height is h = 2.

The area of this trapezoid is

A = h*(b1+b2)/2

A = 2*(15+5)/2

A = 2*20/2

A = 40/2

A = 20

So any vertical cross sectional area is 20 square cm.

Multiply this by the depth of the prism, which is 19, to get the volume of the prism

Volume = (area of cross section)*(depth)

Volume = (20)*(19)

Volume = 380 cubic cm

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4 years ago

Use the substitution method to solve the system of equations: <br><br> 2x – 5y = –14<br> x – 2y = –5

Nutka1998 [239]

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8 0

3 years ago

Read 2 more answers

Learning Task 3:

padilas [110]

Answer:

$Area = x^2- 25$

$Area =9x^2 +24x + 16$

$Length = (3x -2)$

$Speed = \left(y^2-3y+1\right)$

$Product = 3m^3 + 6m^2 - 6m$

Step-by-step explanation:

Solving (1):

$Length = (x + 5)$

$Width = (x - 5)$

Required

Calculate Area

$Area = Length * Width$

$Area = (x + 5) * (x - 5)$

$Area = x^2 + 5x - 5x - 25$

$Area = x^2- 25$

Solving (2):

Given

$Length = (3x + 4)$

Required: Calculate Area

$Area =Length * Length$

$Area =(3x + 4) * (3x + 4)$

$Area =9x^2 + 12x + 12x + 16$

$Area =9x^2 +24x + 16$

Solving (3):

$Area = 3x^2 + 7x - 6$

$Width = x + 3$

Required: Calculate Length

$Area = Length * Width$

$Length = \frac{Area}{Width}$

$Length = \frac{3x^2 + 7x - 6}{x + 3}$

Factorize the numerator

$Length = \frac{3x^2 + 9x -2x - 6}{x + 3}$

$Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}$

$Length = \frac{(3x -2) (x + 3)}{x + 3}$

Divide by x + 3

$Length = (3x -2)$

Solving (4):

$Distance = (2y^3 - 7y^2 + 5y -1)$

$Time = 2y - 1$

Required: Determine the average speed

This is calculated as:

$Speed = \frac{Distance}{Time}$

$Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}$

Factorize the numerator

$Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}$

$Speed = \left(y^2-3y+1\right)$

Solving (5):

Multiply $(m^2 + 2m - 2)$ by sum of $(m + 3)$ and $(2m - 3)$

First, calculate the sum:

$Sum = m + 3 + 2m - 3$

$Sum = m + 2m+3 - 3$

$Sum = 3m$

Then, the product

$Product = (m^2 + 2m - 2)(3m)$

$Product = 3m^3 + 6m^2 - 6m$

6 0

3 years ago

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-6x + 6y= 6<br> -6x + 3y=-12

jeka94

Hope this helps with the answer to your question

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4 years ago

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andrezito [222]

Answer: 4.572

Step-by-step explanation:

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3 years ago

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