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kenny6666 [7]
4 years ago
8

Figure this out please

Mathematics
2 answers:
rusak2 [61]4 years ago
7 0

Answer:

570 cm³

Step-by-step explanation:

Check the rule in your picture about Calculating the volume of a prism:

Volume = (2×15)×19

             = 570

irina [24]4 years ago
6 0
<h3>Answer:  380 cubic cm</h3>

Explanation:

The front and back faces are trapezoids. Focus on one of the trapezoids.

I'll focus on the front face. It has parallel sides of b1 = 15 and b2 = 5. The height is h = 2.

The area of this trapezoid is

A = h*(b1+b2)/2

A = 2*(15+5)/2

A = 2*20/2

A = 40/2

A = 20

So any vertical cross sectional area is 20 square cm.

Multiply this by the depth of the prism, which is 19, to get the volume of the prism

Volume = (area of cross section)*(depth)

Volume = (20)*(19)

Volume = 380 cubic cm

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Use the substitution method to solve the system of equations: <br><br> 2x – 5y = –14<br> x – 2y = –5
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8 0
3 years ago
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Learning Task 3:
padilas [110]

Answer:

Area = x^2- 25

Area =9x^2 +24x + 16

Length = (3x -2)

Speed = \left(y^2-3y+1\right)

Product = 3m^3 + 6m^2 - 6m

Step-by-step explanation:

Solving (1):

Length = (x + 5)

Width = (x - 5)

Required

Calculate Area

Area = Length * Width

Area = (x + 5) * (x - 5)

Area = x^2 + 5x - 5x - 25

Area = x^2- 25

Solving (2):

Given

Length = (3x + 4)

Required: Calculate Area

Area =Length * Length

Area =(3x + 4) * (3x + 4)

Area =9x^2 + 12x + 12x + 16

Area =9x^2 +24x + 16

Solving (3):

Area = 3x^2 + 7x - 6

Width = x + 3

Required: Calculate Length

Area = Length * Width

Length = \frac{Area}{Width}

Length = \frac{3x^2 + 7x - 6}{x + 3}

Factorize the numerator

Length = \frac{3x^2 + 9x -2x - 6}{x + 3}

Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}

Length = \frac{(3x -2) (x + 3)}{x + 3}

Divide by x + 3

Length = (3x -2)

Solving (4):

Distance = (2y^3 - 7y^2 + 5y -1)

Time = 2y - 1

Required: Determine the average speed

This is calculated as:

Speed = \frac{Distance}{Time}

Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}

Factorize the numerator

Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}

Speed = \left(y^2-3y+1\right)

Solving (5):

Multiply (m^2 + 2m - 2) by sum of (m + 3) and (2m - 3)

First, calculate the sum:

Sum = m + 3 + 2m - 3

Sum = m +  2m+3 - 3

Sum = 3m

Then, the product

Product = (m^2 + 2m - 2)(3m)

Product = 3m^3 + 6m^2 - 6m

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3 years ago
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-6x + 6y= 6<br> -6x + 3y=-12
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Hope this helps with the answer to your question

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4 years ago
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15,000 feet to kilometers.
andrezito [222]

Answer: 4.572

Step-by-step explanation:

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3 years ago
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