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qaws [65]
2 years ago
15

How many valence electrons does Oxygen have: a) 3 b) 5 c) 13

Chemistry
2 answers:
Klio2033 [76]2 years ago
8 0

The answer should be 6

ivolga24 [154]2 years ago
4 0

Answer:

it has 6?

Explanation:

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Which of the following statements describes
kozerog [31]

Answer:

Energy is released as heat during the reaction.

5 0
3 years ago
If the half-life of hydrogen-3 is 11.8 years, after two half-lives the radioactivity of a sample will be reduced to one-half of
maw [93]

Answer:

False

Explanation:

Half life is the time period at which the concentration of the radioactive substance in decay reduced to half.

<u>Thus, if the hydrogen-3 has gone 2 half lives, it means that it has first reduced to its half and then again the half of what it was, i.e. 1/4</u>

Thus, after two successive half-lives, the concentration must be 1/4 of the initial concentration and hence, the statement is false.

4 0
3 years ago
if 0.0203 g of a gas dissolves in 1.39 l of water at 1.02 atmospheres at what pressure (in atm) would you be able to dissolve 0.
Sergeu [11.5K]
First, we need to get n1 (no.of moles of water ): when

mass of water = 0.0203 g and the volume = 1.39 L

∴ n1 = mass / molar mass of water

        = 0.0203g / 18 g/mol
        = 0.00113 moles

then we need to get n2 (no of moles of water) after the mass has changed:

when the mass of water = 0.146 g

n2 = mass / molar mass

     = 0.146g / 18 g/ mol
     = 0.008 moles

so by using the ideal gas formula and when the volume is not changed:

So, P1/n1 = P2/n2 

when we have P1 = 1.02 atm 

and n1= 0.00113 moles

and n2 = 0.008 moles 

so we solve for P2 and get the pressure

∴P2 = P1*n2 / n1

        =1.02 atm *0.008 moles / 0.00113 moles

       = 7.22 atm

∴the new pressure will be 7.22 atm


5 0
3 years ago
The wavelength of a particular color of violet light is 433 nm. The energy of this wavelength of light is kJ/photon. (109 nm = 1
mash [69]

Answer:

4.59 × 10⁻³⁶ kJ/photon

Explanation:

Step 1: Given and required data

  • Wavelength of the violet light (λ): 433 nm
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s
  • Speed of light (c): 3.00 × 10⁸ m/s

Step 2: Convert "λ" to meters

We will use the conversion factor 1 m = 10⁹ nm.

433 nm × 1 m/10⁹ nm = 4.33 × 10⁷ m

Step 3: Calculate the energy (E) of the photon

We will use the Planck-Einstein's relation.

E = h × c/λ

E = 6.63 × 10⁻³⁴ J.s × (3.00 × 10⁸ m/s)/4.33 × 10⁷ m

E = 4.59 × 10⁻³³ J = 4.59 × 10⁻³⁶ kJ

5 0
3 years ago
What are your main fears about this class (if any)?​
netineya [11]
This is based on your personal opinion lol but ig you can say public speaking
8 0
3 years ago
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