Answer:
1. Al2O3 + 3H2SO4 —> Al2(SO4)3 + 3H2O
The coefficients are: 1, 3, 1, 3
2. Yes, reaction occurs when ammonium carbonate and chromium(III) nitrate are combined.
The balanced equation for the reaction is given below:
3(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3
The coefficients are: 3, 2, 6, 1
Explanation:
1. The word equation is given below:
aluminum oxide(s) + sulfuric acid(aq) -> aluminum sulfate(aq) + water (l)
The above can be written as:
Al2O3 + H2SO4 —> Al2(SO4)3 + H2O
Now we can balance the equation as follow:
There are 3 atoms of SO4 on the right side and 1 atom on the left. It can be balance by putting 3 in front of H2SO4 as shown below:
Al2O3 + 3H2SO4 —> Al2(SO4)3 + H2O
There are 6 atoms of H on the left side and 2 atoms on the right. It can be balance by putting 3 in front of H2O as shown below:
Al2O3 + 3H2SO4 —> Al2(SO4)3 + 3H2O
Now the equation is balanced
The coefficients are: 1, 3, 1, 3
2. Yes, reaction occurs when ammonium carbonate and chromium(III) nitrate are combined.
The equation for the reaction is given below:
(NH4)2CO3 + Cr(NO3)3 —> NH4NO3 + Cr2(CO3)3
We can balance the equation above as follow:
There are 2 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 2 in front of Cr(NO3)3 as shown below:
(NH4)2CO3 + 2Cr(NO3)3 —> NH4NO3 + Cr2(CO3)3
Now, there are 6 atoms of NO3 on the left side and 1 on the right side. It can be balance by putting 6 in front of NH4NO3 as shown below:
(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3
Now, there are 2 atoms of NH4 on the left side and 6 atoms on the right. It can be balance by putting 3 in front of (NH4)2CO3 as shown below:
3(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3
Now the equation is balanced.
The coefficients are: 3, 2, 6, 1
