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Lorico [155]
3 years ago
9

The compound, (nh4)2s, can be used in analysis for trace amounts of metals present in a sample. what is its name?

Chemistry
2 answers:
nexus9112 [7]3 years ago
7 0
To name compounds, usually, they are a combination of a metal and a nonmetal, between nonmetals and between metals. The two elements here are ammonium (NH₄) and sulfur (S). These are both nonmetals. When you name the compound, start by ammonium, followed by sulfur plus a suffix of -ide. The compound is ammonium sulfide.
lbvjy [14]3 years ago
3 0

<u>Answer:</u> The name of the given compound is ammonium sulfide.

<u>Explanation:</u>

We are given a chemical compound having chemical formula of (NH_4)_2S. This is formed by the combination of ammonium (NH_4^+) ions and sulfur S^{2-} ions.

The given compound is an ionic compound because complete transfer of electrons takes place from one atom to another atom.

The nomenclature of ionic compounds is given by:

  • Positive ion is written first.
  • The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
  • In case of transition metals, the oxidation state are written in roman numerals in bracket in front of positive ions.

Hence, the name of the given compound is ammonium sulfide.

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Roland is measuring a physical property of an object. He records the measurement:
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Answer:

The correct answer is density. See the explanation below, please.

Explanation:

Roland measured density, which is a property that relates mass to volume, having units for example: grams / cm3

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2 years ago
The color change of an indicator is used to determine ​
lisov135 [29]

Answer:

Whether a solution is acidic or basic can be measured on the pH scale. When universal indicator is added to a solution, the color change can indicate the approximate pH of the solution. Acids cause universal indicator solution to change from green toward red. ... Acidic solutions have a pH below 7 on the pH scale.

Explanation:

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3 0
3 years ago
How many electrons are in the highest occupied energy level of a neutral chlorine atom?
tino4ka555 [31]
There are seven electrons
5 0
2 years ago
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Using the fact that at 0.10 M, the absorbance was 0.357; and at 0.20 M, the absorbance was 0.714, the absorptivity (slope) is
olga_2 [115]

Answer:

The answer is "3.57 and 0.07".

Explanation:

Using the slop formula:

=\frac{n_2-n_1}{n_2-n_1}\\\\ =\frac{0.714-0.357}{0.20-0.10} \\\\ = ABSORPTIVITY, \ \ a=3.57 \\\\A= a\times b \times c

Given:

A=0.250

length path b=1  

from calibration it is found that

a=3.57\\\\consentation \ c=\frac{A}{a\times b} \\\\C=\frac{0.250}{3.57\times 1}

   =0.07 \ M

3 0
2 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
Read 2 more answers
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