Answer:
Explanation:
2N₂O(g) → 2N₂(g) + O₂(g)
molecular weight of N₂O = 44
∆Hº = –166.7 kJ/mol
44 g of N₂O decomposes to give 166.7 kJ of heat
2.25 g of N₂O decomposes to give 166.7 x 2.25 / 44 kJ of heat
= 8.51 kJ of heat .
The temperature of the gas sample is 813 K.
<u>Explanation:</u>
We have to use the ideal gas equation to find the temperature of the gas sample.
The ideal gas equation is PV = nRT
Pressure, P = 429 mm Hg = 0.56 atm
Volume, V = 560 mL = 0.56 L
R = gas constant = 0.08205 L atm mol⁻¹K⁻¹
Mass = 0.211 g
Molar mass of carbon di oxide = 44.01 g / mol
Moles, n = 
= 0.0047 mol
Now, we have to plugin the above values in the above equation, we will get the temperature as,

T = 
= 813 K
So the temperature of the gas sample is 813 K.
Answer:
2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)
Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?
ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol
The term "solution" is more frequently used when a homogeneous mixture<span> is a liquid, although it is sometimes used if the </span>homogeneous mixture<span> is a gas.</span>