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3 years ago

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Given the following thermochemical equation 2N2O(g) → 2N2(g) + O2(g) ∆Hº = –166.7 kJ/mol find the amount of heat that will be pr

oduced when a 2.25 g sample of N2O(g) decomposes into N2 and O2.A. 8.51 kJB. 4.25 kJC. 74.1 kJD. 2.13 kJE. 37.1 kJ

1 answer:

soldi70 [24.7K]3 years ago

5 0

Answer:

Explanation:

2N₂O(g) → 2N₂(g) + O₂(g)

molecular weight of N₂O = 44

∆Hº = –166.7 kJ/mol

44 g of N₂O decomposes to give 166.7 kJ of heat

2.25 g of N₂O decomposes to give 166.7 x 2.25 / 44 kJ of heat

= 8.51 kJ of heat .

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You need to produce a buffer solution that has a pH of 5.26. You already have a solution that contains 10. mmol (millimoles) of

Andreas93 [3]

The question is incomplete, complete question is :

You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.

Answer:

33.11 millimoles of acetate we will need to add to this solution.

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

Where :

tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid

[salt] = Concentration of salt

[Acid] = Concentration of salt

We have:

pH = 5.26

$pK_a=4.74$

[salt] = $[CH_3COO^-]$ = ?

[acid] = $[CH_3COOH]=10.0 mmol$

$5.26=4.74+\log(\frac{[CH_3COO^-]}{[10.0 mmol]})$

$[CH_3COO^-]=33.11 mmol$

33.11 millimoles of acetate we will need to add to this solution.

3 0

4 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

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3 years ago

Coal,oil,and natural gas are examples of earths _______<br><br> Fill out the blank

Aleks04 [339]

Non renewable resources

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3 years ago

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Granitic igneous rocks are all of the following EXCEPT ____.

baherus [9]

Answer:

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Explanation:

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3 years ago

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What is the wavelength of electromagnetic radiation with a frequency of 9.23 × 10^-7 Hz?

stich3 [128]

3.25 x 10¹⁴m

Explanation:

Given parameters:

Frequency of the radiation = 9.23 x 10⁻⁷hz

Unknown:

Wavelength of the radiation = ?

Solution:

The velocity of electromagnetic radiation is the same as that of the speed of light in vacuums.

Velocity = frequency x wavelength.

Velocity = 3 x 10⁸m/s

Since the unknown is wavelength, we factor it out:

Wavelength = $\frac{Velocity }{frequency}$

Wavelength = $\frac{x}{y}$ $\frac{ 3 x 10^{8} }{9.23 x 10^{-7} }$

= 3.25 x 10¹⁴m

learn more:

Wavelength brainly.com/question/6352445

#learnwithBrainly

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3 years ago