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3 years ago

8

A nautical mile is 6076 feet, and 1 knot is a unit of speed equal to 1 nautical mile/hour. How fast is a boat going 8 knots goin

g in feet/s

1 answer:

mezya [45]3 years ago

5 0

Answer:

The speed of the boat is equal to 13.50 ft/s.

Explanation:

given,

1 nautical mile = 6076 ft

1 knot = 1 nautical mile /hour

1 knot = 6076 ft/hr

speed of boat = 8 knots

8 knots = 8 nautical mile /hour

= $8 \times \dfrac{6076\ ft}{1\nautical\ mile}\times \dfrac{1\ hour}{60\times 60\ s}$

= 13.50 ft/s

The speed of the boat is equal to 13.50 ft/s.

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What is a particulate ? Name a couple of examples.

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3. Imagine a 10kg block moving with a speed of 20m/s<br> calculate the kinetic energy of this block

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To practice Problem-Solving Strategy 17.1 for wave interference problems. Two loudspeakers are placed side by side a distance d

Nimfa-mama [501]

Complete Question

The compete question is shown on the first uploaded question

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Explanation:

From the question we are told that

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Generally the distance of the listener to the first speaker is mathematically represented as

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Generally the distance of the listener to second speaker at its new position is

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$pD = L_2 - L_1 = \frac{n * \lambda}{2}$

Here $\lambda$ is the wavelength which is mathematically represented as

$\lambda = \frac{v}{f}$

=> $L_2 - L_1 = \frac{n * \frac{v}{f}}{2}$

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=> $L_2 - L_1 = \frac{n * v}{2f}$

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3 years ago

A projectile is launched into the air with the initial speed of vi = 40 m/s at a launch angle of 20 degrees above the horizontal

Sphinxa [80]

The range of the projectile is 188 m

Explanation:

The motion of the arrow in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

The path of a projectile is the combination of these two motions: see figure in attachment.

In order to find the horizontal range of the projectile, we just need to calculate the horizontal distance travelled.

We have:

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$v_x = v_i cos \theta$

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$d=v_x t = (37.6)(5.0)=188 m$

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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3 years ago