Question

A train slows from 44 m/s to 19 m/s in 9 seconds. What is the train's acceleration? Show your work.

Answer 1

Answer:

a = 2.77 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f} =v_{o} -a*t$

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 44 [m/s]

a = acceleration [m/s²]

t = time = 9 [s]

Note: The negative sign in the above equation means that the train is decreasing its velocity.

19 = 44 - a*9

9*a = 44 -19

a = 2.77 [m/s²]