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liq [111]
3 years ago
6

Match the equation to the answer

Mathematics
1 answer:
Nostrana [21]3 years ago
5 0

Answer:

1) 15yx+ 4y  

2) 4yx+6y  

3) 4yx+8y  

4)21yx+6y

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What are some examples of irrational numbers
vaieri [72.5K]
Common Examples of Irrational Numbers
Pi, which begins with 3.14, is one of the most common irrational numbers. ...
e, also known as Euler's number, is another common irrational number. ...
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6 0
3 years ago
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Find the angle to the nearest degree. *<br> sin-10.5166<br> 1<br> 31.1°<br> 58.9°<br> 0.5°
Mice21 [21]

Given:

The given inverse trigonometric term is:

\sin^{-1}(0.5166)

To find:

The value given inverse trigonometric term.

Solution:

We have,

\sin^{-1}(0.5166)

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3 years ago
Based only on the information given in the diagram, which congruence theorems or postulates could be given as reasons why DEF=JK
NISA [10]

Answer:

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Step-by-step explanation:

AAS is the Angle-Angle-Side congruence statement.  It says that if two angles and a non-included side of one triangle are congruent to the corresponding two angles and non-included side of a second triangle, then the triangles are congruent.  In these triangles, ∠E≅∠K, ∠F≅∠L, and DE≅JK.  These are two angles and a non-included side; this is AAS.

LA is the leg-acute theorem.  It states that if a leg and acute angle of one triangle is congruent to the corresponding leg and acute angle of another triangle, then the triangles are congruent.

The leg we have congruent from each triangle is DE and JK.  We also have ∠E≅∠K and ∠F≅∠L, both pairs of which are acute.  This is the LA theorem.

ASA is the Angle-Side-Angle congruence statement.  It says that if two angles and an included side of one triangle are congruent to the corresponding two angles and included side of another triangle, then the triangles are congruent.  

We have that ∠D≅∠J, DE≅JK and ∠E≅∠K.  This gives us two angles and an included side, or ASA.

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3 years ago
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kondaur [170]

(8m^2+m+7m^2)-(3m-4m^3+2m^2)\\\\=8m^2+m+7m^2-3m+4m^3-2m^2\qquad|\text{combine like terms}\\\\=(4m^3)+(8m^2+7m^2-2m^2)+(m-3m)\\\\=4m^3+13m^2-2m

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