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STALIN [3.7K]
3 years ago
12

A 290-kg flatcar 28 m long is moving with a speed of 6.5 m/s along horizontal frictionless rails. A 95-kg worker starts walking

from one end of the car to the other in the direction of motion, with speed 3.0 m/s with respect to the car. In the time it takes for him to reach the other end, how far has the flatcar moved?
Mathematics
1 answer:
blsea [12.9K]3 years ago
6 0

Answer:

9.33 seconds

60.67 meters

Step-by-step explanation:

A worker with a speed of 3.0 m/s with respect to a car, starts to walk from one end of the car to the other in the direction of motion of the car.

As the car is 28 m long, then the worker will reach the other end of the car in \frac{28}{3} = 9.33 seconds. (Answer)

Now, the car is moving with a speed of 6.5 m/s and in the time of 9.33 seconds, it will move by 6.5 \times 9.33 = 60.67 meters. (Answer)

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