Question

A 290-kg flatcar 28 m long is moving with a speed of 6.5 m/s along horizontal frictionless rails. A 95-kg worker starts walking from one end of the car to the other in the direction of motion, with speed 3.0 m/s with respect to the car. In the time it takes for him to reach the other end, how far has the flatcar moved?

Answer 1

Answer:

9.33 seconds

60.67 meters

Step-by-step explanation:

A worker with a speed of 3.0 m/s with respect to a car, starts to walk from one end of the car to the other in the direction of motion of the car.

As the car is 28 m long, then the worker will reach the other end of the car in $\frac{28}{3} = 9.33$ seconds. (Answer)

Now, the car is moving with a speed of 6.5 m/s and in the time of 9.33 seconds, it will move by $6.5 \times 9.33 = 60.67$ meters. (Answer)