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jeka57 [31]
3 years ago
13

Example of a metal, nonmetal, and metalloid WILL GET BRAINLIEST!!

Chemistry
2 answers:
STatiana [176]3 years ago
5 0

Answer:

metal= copper nonmetal= nitrogen metalloid= silicon

Explanation:

hope this helps

Anuta_ua [19.1K]3 years ago
4 0

Answer:

ferum (Fe), chlorine (Cl), silicon (Si)

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Why is oiling done time and again in a sewing machine​
AnnZ [28]

Answer:

Oiling is done on a regular basis to sewing Machine because in the machine there are lots of machinery parts i.e. wheels and axels, etc. which are in continuous use and they possess so much frictional force between them that wear tear may be observed in those parts.

8 0
3 years ago
Read 2 more answers
Help!!!!!!!!!!!!!!!!!!
skad [1K]

The density of the sample : 0.827 g/L

<h3>Further explanation</h3>

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm , N/m²

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m2, v= m³)

T = temperature, Kelvin  

n= 1 mol

MW Neon = 20,1797 g/mol

mass of Neon :

\tt mass=mol\times MW\\\\mass=1\times 20,1797 =20.1797~g

The density of the sample :

\tt \rho=\dfrac{m}{V}\\\\\rho=\dfrac{20,1797}{24.4}=0.827~g/L

or We can use the ideal gas formula ta find density :

\tt \rho=\dfrac{P\times MW}{RT}\\\\\rho=\dfrac{1\times 20.1797}{0.082\times 298}\\\\\rho=0.826~g/L

8 0
3 years ago
In what way is sedimentary rock formed in nature with a sieve
ella [17]
Sedimentary rock is made of Brocken down rocks and living things.
4 0
3 years ago
What is the percent by mass of carbon in c10 h14 n2?
bonufazy [111]
Add all weighs together
calculate carbons weigh
(carb weigh/total)×100
3 0
3 years ago
An unknown compound is processed using elemental analysis and found to contain 117.4g of platinum 28.91 carbon and 33.71g nitrog
dlinn [17]

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

8 0
3 years ago
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