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Svetach [21]
2 years ago
12

How many atoms of each element are in NaCI?

Chemistry
1 answer:
gavmur [86]2 years ago
3 0

Answer:

well first you need 1 s then you need 1 ch

Explanation:

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What is polyethylene??defination​
rewona [7]

Answer:

a tough, light, flexible synthetic resin made by polymerizing ethylene, chiefly used for plastic bags, food containers, and other packaging.

Explanation:

8 0
3 years ago
Read 2 more answers
B. The heat of reaction for the process described in (a) can be determined by
julsineya [31]

Answer: I believe the 1st and 3rd reactions are better obtained through reference sources and the 2nd and 4th are easiest and safest to measure in the laboratory.

Explanation:

I am also working on this Pre-lab right now, and I looked back at the first question to help get my answer. In the first question (a), it is noted that ammonia gas and gaseous hydrochloric acid are both potentially dangerous in gaseous form. I saw that both the 1st and 3rd reactions contained noxious gases (I knew this because there was a (g) in both of these reactions). Using the knowledge from the first question that the noxious gases were potentially dangerous, I assumed that those reactions were the ones that are better obtained through the reference sources. The 2nd and 4th reactions did not contain any noxious gases, so I assumed those ones were easiest and safest to measure in the laboratory. Hope this helps!

7 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!
Akimi4 [234]

Answser

i didnt do dis my mom has a answer key book

Explanation:

4 0
3 years ago
Rachel burns a 53 gram cracker under a soda can filled with 81.6 grams of water. She took the temperature of the water before sh
Anna11 [10]

Answer

Q=4479.8 cal

Procedure

To solve the problem you will need to use the specific heat formula

Q=mc\Delta T

Where;

Q=heat energy

m=mass

c=specific heat capacity

ΔT=change in temperature

Assuming that the heat released from the cracker of unknown material is equal to the heat absorbed by the water, then we can use the c and m for water in our calculations.

c_{water}=4.186\frac{J}{g\degree C}

Substituting the values in our equation we have

Q=mc\Delta T=81.6\text{ }g(4.186\frac{J}{g\degree C})(68.1-13.2)\degree C=18752.61\text{ }J

Finally, transform the J to cal

18752.61\text{ }J\frac{1\text{ }cal}{4.186\text{ }J}=4479.8\text{ cal}

8 0
1 year ago
Can someone help me please
Romashka [77]
True, False , and I think the last one is true
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3 years ago
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