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AlekseyPX
1 year ago
5

Hello i need help with this!!​

Physics
1 answer:
mr Goodwill [35]1 year ago
3 0

Answer:

Yes

Explanation:

If lamp A burnt out there would still be a wire above it that connects lamp B and C to the power source

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borishaifa [10]

Answer:

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Explanation:

bruh

6 0
2 years ago
Read 2 more answers
I have a set of calipers that can measure thickness of a few inches with an uncertainty of ±0.005 inches. I measure the thicknes
Shtirlitz [24]

Answer:

(a) 0.0113 ±0.0001 inches

(b) 5 decks

Explanation:

<u>Given information</u>

52 cards, thickness is 0.590 ±0.005 inches

Since this is thickness of all the cards, to get the thickness of a single card we divide the total thickness (plus uncertainty) by the number of cards hence

1 card=\frac {0.590}{52}±\frac {0.005}{52}= 0.0113461 ±0.000096 inches

Considering that thickness is given to 3 significant figures while uncertainty is to 1 significant figure, the final answer should also conform to these hence giving the first part of the answer to 3 significant figures while second part to 1 significant figure yields 0.0113 ±0.0001 inches

(b)

Considering that the cards have uncertainty of 0.0001 inches and the number of decks, n required to create uncertainty of 0.00002 inch is given by

n=\frac {0.0001}{0.00002}=5

We need 5 decks for the given uncertainty

4 0
3 years ago
Are the two bulbs acting as current dividers or potential dividers? Explain your answer​
erastova [34]
Circuits are also known as current divider circuits because, in these circuits, the current is divided through each resistor. Whereas, series circuits are known as voltage divider circuits because here voltage is divided across all the resistors.
3 0
1 year ago
Problem 6.056 Air enters a compressor operating at steady state at 15 lbf/in.2, 80°F and exits at 275°F. Stray heat transfer and
vova2212 [387]

To solve this process it is necessary to consider the concepts related to the relations between pressure and temperature in an adiabatic process.

By definition the relationship between pressure and temperature is given by

(\frac{P_2}{P_1})=(\frac{T_2}{T_1})^{(\frac{\gamma}{\gamma-1})}

Here

P = Pressure

T = Temperature

\gamma =The ratio of specific heats. For air normally is 1.4.

Our values are given as,

P_1 = 15lb/in^2\\T_1= 80\°F = 299.817K\\T_2 =400\°F = 408.15K

Therefore replacing we have,

(\frac{P_2}{P_1})=(\frac{T_2}{T_1})^{(\frac{\gamma}{\gamma-1})}

(\frac{P_2}{15})=(\frac{408.15}{299.817})^{(\frac{1.4}{1.4-1})}

Solving for P_2,

P_2 = 15*(\frac{408.15}{299.817})^{(\frac{1.4}{1.4-1})}

P_2 = 44.15Lbf/in^2

Therefore the maximum theoretical pressure at the exit is 44.15Lbf/in^2

5 0
3 years ago
Calculate the index of refraction for a medium in which the speed of light is 2.1x 108 m/s. The speed of light in vacuum is 3x10
strojnjashka [21]

Answer:

n = 1.42

Explanation:

The refractive index for a medium is given by the ratio of the speed of light in vacuum to the speed of light in a medium.

n=\dfrac{c}{v}\\\\n=\dfrac{3\times 10^8}{2.1\times 10^8}\\\\n = 1.42

So, the refractive index of the medium is 1.42.

5 0
3 years ago
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