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3 years ago

6

A deuteron consists of one proton and one neutron. A deuteron moving horizontally enters a uniform, vertical magnetic field of 0

.500 T. It then travels in a circular arc of radius 55.6 cm. How fast was the deuteron moving just before it entered the field? Let the mass of the deuteron m = 3.34 × 10^–27 kg and the charge on a proton q = 1.60 × 10^–19 C. (1 point)

1 answer:

Helen [10]3 years ago

6 0

Answer:

Explanation:

Let the velocity of deuteron be v then force on it in magnetic field

Bqv , B is magnetic field and q is charge on deuteron . This force will provide centripetal force for circular path so

mv² / r = Bqv m is mass of deuteron and r is radius of circular path

v = Bqr / m

(.5 x 1.6 x 10⁻¹⁹ x 55.6 x 10⁻² )/ 3.34 x 10⁻²⁷

= 13.31 x 10⁶ m /s

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