1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lisa [10]
3 years ago
7

A mixture of CrBr3 and inert material is analyzed to determine the Cr content. First the mixture is dissolved in water. Then all

of the bromide ion is precipitated as AgBr by the addition of an excess of silver nitrate. CrBr3(aq) + 3AgNO3(aq) 3AgBr(s) + Cr(NO3)3(aq) In one experiment, a 0.8409 g sample of the mixture resulted in 1.0638 g of AgBr. Determine the percent (by mass) of Cr in the mixture.
Chemistry
1 answer:
Masteriza [31]3 years ago
5 0

Answer:

Mass% Cr = 85.5%

Explanation:

<u>Given:</u>

Mass of CrBr3 sample = 0.8409 g

Mass of the AgBr precipitate = 1.0638 g

<u>To determine:</u>

The mass percent of Cr in the sample

<u>Calculation:</u>

The reaction of CrBr3 with silver nitrate results in the precipitation of the bromide ion as silver chloride (AgBr) and Cr as soluble Cr(NO3)2

CrBr3(aq) + 3AgNO3(aq)→ 3AgBr(s) + Cr(NO3)3(aq)

Molecular weight of AgBr =187.77 g/mol

Moles of AgBr precipitated is:

Moles(AgBr)=\frac{Mass(AgBr)}{Mol.wt(AgBr)}=\frac{0.8409g}{187.77g/mol}=0.004478moles

Since 1 mole of AgBr contains 1 mole of Cl, therefore:

# moles of Cl = 0.004478 moles

At wt of Cl = 35.45 g/mol

Mass(Chloride)=moles*at.wt = .004478moles*34.45g/mol=0.1543

Mass%(chloride)=\frac{mass(chloride)}{mass(sample)}*100=\frac{0.1543}{1.0638}*100 = 14.50%

Mass%(Cr) = 100 - 14.50=85.5%

You might be interested in
Under which conditions will sugar most likely dissolve fastest in a cup of water?
zheka24 [161]
If the cup of water contained hot water. Sugar will dissolve a lot slower if it was in room temperature and even slower if it was in cold water.
3 0
3 years ago
Why are carbon and nitrogen essential for survival to all living organisms? A.
bagirrra123 [75]
Hello there.

<span>Why are carbon and nitrogen essential for survival to all living organisms?
</span>
<span>They are needed to release the energy stored in food.
</span>Therefore, The correct answer would be Option B.
3 0
3 years ago
Read 2 more answers
Jane is sliding down a slide. What kind of motion is she demonstrating?
svp [43]
It is translational motion. i know because i found it on this site. its verified too, have a nice day
5 0
3 years ago
Read 2 more answers
Which of the following best describes a possible carbon compound?
swat32

Answer:One carbon atom forms a double bond with an oxygen atom and two single bonds with two hydrogen atoms

Explanation:

6 0
3 years ago
Read 2 more answers
Drag and drop the labels provided into the boxes below to explain how the Earth-Sun-Moon system results in these seasons on Eart
GalinKa [24]
In order: tilted, rotates, revolving.
6 0
2 years ago
Other questions:
  • This is the last one thank you to anyone who helps ​
    15·2 answers
  • The temperature is -14°C the air pressure in an automobile tire is 149K PA if the volume does not change what is the pressure af
    12·1 answer
  • Under the proper conditions, bromomethane (ch3br) will react with potassium hydroxide (koh) to form _____ and a salt. methanol (
    12·2 answers
  • 3.. Which type of graph would be most helpful for comparing the calorie-content in a variety of
    5·1 answer
  • Which statement best describes how electrons fill orbitals in the periodic table? Electrons fill orbitals in order of their incr
    12·2 answers
  • using hookes law, F s p r i n g = k^x , find the force needed to stretch a spring 2 cm if it has an elastic constant of 3 N/cm
    9·2 answers
  • How can atoms be neutral if they contain charged particles?
    6·1 answer
  • What is the pH of a solution with a [H+] = 1.0 x 10-5
    7·1 answer
  • What is the electron configuration for fluorine?
    13·2 answers
  • What is past form of be<br>​
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!