Answer:
heat reaches to us from the sun through radiation since there is no medium in space, radiation is the major wat heat travels in space.
Answer:
(a). The velocity of star is
and the direction of star toward the earth.
(b). The shift is 0.0168 nm.
Explanation:
Given that,
Wavelength of spectral line = 663 nm
Wavelength of spectral line in lab = 645 nm
(a). We need to calculate the velocity
Using doppler's effect

Where,
= change in wavelength
v = velocity
c = speed of light
Put the value into the formula




The direction of star toward the earth.
(b). Speed = 7800 m/s
We need to calculate the shift
Using formula of shift

Put the value into the formula


This shift is small compare to the the movement of Earth around the sun.
Hence, (a). The velocity of star is
and the direction of star toward the earth.
(b). The shift is 0.0168 nm.
Answer:
The correct option is
a. v = 
Explanation:
Time at which the object start fall t = 0
The acceleration a is given by a = g - bV
Where V = Speed of the object
Speed V² = u² + 2·a·h
However with the drag force the object will approach terminal velocity as t becomes progressively larger whereby v will stop increasing
Option a. is the only option that has limiting value of v which is in the range of g as t increases ∴ option a. is the correct option.
v =
as t increases
→ 1 s and v→ g/b m/s
The relationship between electrical and charge force is that electrical force strengthens and increases the energy pulses and reflects off an object and makes the force about two times greater with charge.
First, we will get the distance traveled before the driver applied the brakes.
distance = velocity * time
distance = 25*0.34 = 8.5 m
Now, we will calculated the distance that the car traveled after the driver applied the brakes. To do this, we will use the equation of motion:
<span>vf^2 = vi^2 + 2*a*d where:
</span>vf = zero, vi = 25 m/s and a = -7 m/s^2
Note: The negative sign is only to show deceleration
d = <span> 1/2*(625) /(7) = 44.6428 m
The total stopping distance =</span> 8.5 + 44.6428 = 53.1428 m