Answer:
Since the astronaut drops the rock, the initial velocity of the rock is 0 m/s
<u>We are given:</u>
initial velocity (u) = 0 m/s
final velocity (v) = v m/s
acceleration (a) = 1.62 m/s/s
height (h) = 1.25 m
<u>Solving for v:</u>
From the third equation of motion:
v²-u² = 2ah
replacing the variables
v² - (0)² =2 (1.62)(1.25)
v² = 1.62 * 2.5
v² = 4 (approx)
v = √4
v = 2 m/s
The speed of the rock just before it lands is 2 m/s
Answer:
2.204x10^2 -2 = 0.02204 in scientific notation.
Answer:
a = 5
Explanation:
F = M × A
15 = 3 × a
a = 15 / 3
a = 5
This is only if the toy can is pushing the book or smth coz the question looks incomplete...?
How does the angle of incoming light compare to the angle of light reflecting off of the surface?
- <em>The measurements of the angles are equal.</em>
<u>For</u><u> </u><u>a</u><u> </u><u>smooth</u><u> </u><u>surface</u><u>,</u><u> </u><u>The</u><u> </u><u>angle</u><u> </u><u>of</u><u> </u><u>reflection</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>angle</u><u> </u><u>of</u><u> </u><u>incidence</u><u> </u><u>are</u><u> </u><u>equal</u><u>.</u>