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uysha [10]
4 years ago
6

Why does range of motion need to be measured separately for each joint

Physics
1 answer:
telo118 [61]4 years ago
6 0
Because each joint is capable of a different measure of its own range of motion
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How does heat reach to us from the sun<br><br><br>​
patriot [66]

Answer:

heat reaches to us from the sun through radiation since there is no medium in space, radiation is the major wat heat travels in space.

6 0
4 years ago
Astronomers observe a spectral analysis of a distant star where a particular element has a spectral line with a wavelength of 66
tekilochka [14]

Answer:

(a). The velocity of star is 8.1\times10^{6}\ m/s and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

Explanation:

Given that,

Wavelength of spectral line = 663 nm

Wavelength of spectral line in lab = 645 nm

(a). We need to calculate the velocity

Using doppler's effect

\Delta \lambda=\dfrac{v}{c}\lambda

Where, \Delta\lambda= change in wavelength

v = velocity

c = speed of light

Put the value into the formula

663-645=\dfrac{v}{3\times10^{8}}\times663

v=\dfrac{3\times10^{8}(663-645)}{663}

v=8144796.38\ m/s

v=8.1\times10^{6}\ m/s

The direction of star toward the earth.

(b). Speed = 7800 m/s

We need to calculate the shift

Using formula of shift

\Delta \lambda=\lambda(\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}-1)

Put the value into the formula

\Delta \lambda=645\times(\sqrt{\dfrac{1+\dfrac{7800}{3\times10^{8}}}{1-\dfrac{7800}{3\times10^{8}}}}-1)

\Delta\lambda=0.0168\ nm

This shift is small compare to the the movement of Earth around the sun.

Hence, (a). The velocity of star is 8.1\times10^{6}\ m/s and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

7 0
3 years ago
An object is released from rest at time t = 0 and falls through the air, which exerts a resistive force such that the accelerati
lubasha [3.4K]

Answer:

The correct option is

a. v = g (1-e^{-bt})/b

Explanation:

Time at which the object start fall t = 0

The acceleration a is given by a = g - bV

Where V = Speed of the object

Speed V² = u² + 2·a·h

However with the drag force the object will approach terminal velocity as t becomes progressively larger whereby v will stop increasing

Option a. is the only option that has  limiting value of v which is in the range of g as t increases ∴ option a. is the correct option.

v = g (1-e^{-bt})/b  as t increases (1-e^{-bt}) → 1 s and v→ g/b m/s

6 0
3 years ago
Explain the relationship between electrical charge and force.
Radda [10]
The relationship between electrical and charge force is that electrical force strengthens and increases the energy pulses and reflects off an object and makes the force about two times greater with charge.
7 0
3 years ago
Suppose a car is traveling at +25.0 m/s, and the driver sees a traffic light turn red. After 0.340 s has elapsed (the reaction t
scoundrel [369]
First, we will get the distance traveled before the driver applied the brakes.
distance = velocity * time
distance = 25*0.34 = 8.5 m

Now, we will calculated the distance that the car traveled after the driver applied the brakes. To do this, we will use the equation of motion:
<span>vf^2 = vi^2 + 2*a*d where:
</span>vf = zero, vi = 25 m/s and a = -7 m/s^2
Note: The negative sign is only to show deceleration 
d = <span> 1/2*(625) /(7) = 44.6428 m

The total stopping distance =</span> 8.5 + 44.6428 = 53.1428 m
3 0
3 years ago
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