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tester [92]
3 years ago
15

Helpppppp please!!!!!

Physics
2 answers:
Valentin [98]3 years ago
8 0

Answer:

6 m/s

Explanation:

Velocity = Distance/Time

              = 84 meters/14 seconds

              = 6 m/s

Hope this helps! :)

Mice21 [21]3 years ago
7 0

Answer:

6

Explanation:

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List some ways houses would be built differently if gravity were much stronger or much weaker ?two
tia_tia [17]

Answer:

If gravity were stronger, houses and buildings would have to be more sturdy so they do not get crushed to the ground. If gravity were weaker, buildings and houses would have to be built stronger so they do not float away.

Hope this helps you!

8 0
3 years ago
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Three-dimensional ____ programs allow designers to rotate designs of 3-d objects to view them from any angle.
notsponge [240]
Long phrase is the blank
5 0
3 years ago
A circuit is built based on this circuit diagram. What is the equivalent resistance of the circuit?
Dmitry_Shevchenko [17]
The three resistors are connected to the same points of the circuit, so they are in parallel configuration. The equivalent resistance of 3 resistors in parallel is given by:
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3}
If we plug the values of the resistances into the formula, we find
\frac{1}{R_{eq}}= \frac{1}{3.0 \Omega}+ \frac{1}{6.0 \Omega}+ \frac{1}{9.0 \Omega}= \frac{6+3+2}{18.0 \Omega} = \frac{11}{18.0 \Omega}
From which we find the equivalent resistance:
R_{eq} =  \frac{18.0}{11} \Omega =1.6 \Omega

So, the correct answer is B.
7 0
2 years ago
A nearsighted person wants to see an apple that is 7 meters away but can only clearly see objects that are at most 62 cm away fr
natulia [17]

Answer:

The power of the corrective lenses is 3.162 D.

Explanation:

Given that,

Object distance = 70 cm

Image distance = 62 cm

Distance between eyes and glasses = 2.5 cm

Eyeglasses made of diverging corrective lenses can help her to see the apple clearly

So now ,

Object distance from glass =70-2.5 = 67.5 cm

Image distance from glass = 62-2.5 = 59.5 cm

We need to calculate the focal length

Using formula for focal length

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

\dfrac{1}{f}=-\dfrac{1}{59.5}-\dfrac{1}{67.5}

\dfrac{1}{f}=-\dfrac{508}{16065}\ cm

We need to calculate the power of lens

Using formula of power

P=\dfrac{100}{f}

P=-\dfrac{508}{16065}\times100

P=-3.162 \ D

Negative sign shows the lens is diverging.

Hence, The power of the corrective lenses is 3.162 D.

6 0
3 years ago
A 50n box is lifted 2 meters in 3 seconds.
anygoal [31]

F=G=50 N

L=F*d=50*2=100 J

is the work

P=L/t=100/3=33.33 W

4 0
3 years ago
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