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3 years ago

Helpppppp please!!!!!

Physics

2 answers:

Valentin [98]3 years ago

8 0

Answer:

6 m/s

Explanation:

Velocity = Distance/Time

= 84 meters/14 seconds

= 6 m/s

Hope this helps! :)

Mice21 [21]3 years ago

7 0

Answer:

Explanation:

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Beryllium has a charge of +2, and bromine has a charge of –1. Which is the best name for the ionic bond that forms between them?

Feliz [49]

Answer:

Beryllium bromide

Explanation:

There exists 2 elements in the question

Beryllium Be with valence of +2, and it's a metal

Bromine Br with a valence of -1, and is a non - metal.

Both of them combine together forming an ionic bond:

Be + Br(2) -> BeBr(2)

In naming the compound, we would say that since the first is a metal, beryllium, and the second being a halogen, bromine. We name it by calling the first name together with the last name and changing the last name of the non metal from -ine to -ide.

So we have, Beryllium Bromide.

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3 years ago

Which best describes most covalent compounds? resilient brittle cold warm

Ugo [173]

Answer:

B) brittle

Explanation:

This describes most covalent compounds.

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3 years ago

Read 2 more answers

Not sure if this is a physics question but how do I find the formula using ohms law..any one

Ne4ueva [31]

Physics is as good a place as any, I guess.

And, before we roll up our sleeves, may I also note that assigning 48 fill-ins
(4 each for 12 problems) is exceeded in its excess only by expecting all of
the answers in return for 5 points. I'll give you the tips and hints you need
in order to solve these, and then I'll wish you well.

I see from the label in the upper corner that all of this refers to series circuits.
That's important to know, and I was about to ask. So we're going to assume
that for the whole bunch on the page, R1 and R2 are in series, connected
across VS, and there are no other components involved besides the two
resistors.

OK. Here are the tools you need:

On a resistor . . .
   ' K ' = 'thousand'
   ' Meg ' = 'million'

Total resistance . . . RT = R1 + R2 ohms

Voltage across each resistor:
VR1 = VS [ R1 / (R1+R2) ] volts

VR2 = VS [ R2 / (R1+R2) ]    volts

Total current in the series circuit:
   IT = VS / RT = VS / (R1+R2) Amps

And that's it. Easier than I thought. There are some other things that
it could have asked for, but it didn't.

Example:
Line #4:
VS = 5 volts
R1 = 470 ohms
R2 = 1,000 ohms

RT = R1 + R2 = 1,470 ohms

VR1 = VS ( R1/RT ) = 5 (470 / 1,470) = 1.598... volts
VR2 = VS ( R2/RT ) = 5 (1,000 / 1,470) = 3.401 volts

(Notice that VR1 + VR2 always = VS.)

IT = VS / RT = 5 / 1,470 = 0.0034 Amperes = 3.4 mA (milliamps)

The power supplied by the battery is (VS)²/RT = 0.017 watt ,
but it doesn't ask for that.

And that's it ! That's everything you need. Go get 'em, champ !

7 0

3 years ago

An object is propelled straight up from ground level with an initial velocity of 48 feet per second. Its height at time t is mod

Ket [755]

Answer:

Explanation:

For a. its max height and when it occurs. First the max height. That's a y-dimension thing, and in the y-dimension we have this info:

v₀ = 48 ft/s

a = -32 ft/s/s

v = 0 (the max height of an object occurs when the final velocity of the object is 0). Use the following equation for this part of the problem:

v² = v₀² + 2aΔx and filling in:

$0=48^2+2(-32)$ Δx and

0 = 2300 - 64Δx and

-2300 = -64Δs so

Δx = 36 feet.

Now for the time it takes to get to this max height. Final velocity is still 0 here, but the equation is a different one for this part of the problem. Use:

v = v₀ + at and filling in:

0 = 48 - 32t and

-48 = -32t so

t = 1.5 sec. That's part a. Onto part b:

The object hits the ground when its displacement, Δx, is 0. Use this equation for this problem:

Δx = v₀t + $\frac{1}{2}at^2$ and filling in:

$0=48t+\frac{1}{2}(-32)t^2$ and

$0=48t-16t^2$ and

0 = 16t(3 - t) so

t = 0 and t = 3. t = 0 is before the object is propelled, so it makes sense that at 0 seconds, the object was still on the ground, right? Then at 3 seconds, it's back on the ground. (Isn't math just perfectly, beautifully sensible!?) Now onto part c:

We are looking for the time interval when the object is >32 feet. So we use the same equation we just used, but with an inequality instead of an equals sign:

$48t+\frac{1}{2}(-32)t^2 >32$ and get everything on one side and factor it again:

$-16t^2+48t-32>0$ and we find that

1 < t < 2 so the time interval is between 1 and 2 seconds that the object is over 32 feet in the air.

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3 years ago

The energy goes from _____ to the _____ above it.

Artist 52 [7]

Answer:

The energy goes from the ground state to the excited states above it.

4 0

3 years ago