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balu736 [363]
3 years ago
12

Aluminum has a density of

Physics
2 answers:
Morgarella [4.7K]3 years ago
7 0

Answer:

0.1848

Explanation:

p=m/v

where

p=density

m=mass

v=volume

Substitute the values and solve

the answer is 0.1848

BTW, it is correct for Acellus students

agasfer [191]3 years ago
3 0

<h3><u>Volume is 0.1848 m³</u></h3><h3 />

Explanation:

<h2>Given:</h2>

m = 49.9 kg

ρ = 270 kg/m³

<h2>Required:</h2>

volume

<h2>Equation:</h2>

ρ \:= \:\frac{m}{v}

where: ρ - density

m - mass

v - volume

<h2>Solution:</h2>

Substitute the value of ρ and m

ρ \:= \:\frac{m}{v}

270\: kg/m³\:= \:\frac{49.9\:kg}{v}

(v)\:270\: kg/m³\:= \:49.9\:kg

v\:= \:\frac{49.9\:kg}{270\: kg/m³}

v\:= \:0.1848\:m³

<h2>Final Answer:</h2><h3><u>Volume is 0.1848 m³</u></h3>
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Answer:

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Explanation:

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k=\frac{C}{C_0}=\frac{3.0 nF}{1.2 nF}=2.5

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3 years ago
You are driving at 35 m/s east and notice another car that is initially located 462 m in front of you and is moving east at 25 m
GaryK [48]

The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture.  Car 1 travels at 35m/s and Car 2 travels at 25m/s.  Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second.  So we can interpret Car 1's relative velocity to Car 2 as 10m/s.  Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.

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So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up.  So we have to use Car 1's velocity and not the relative velocity:

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prohojiy [21]

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where m is the mass of the object and v its speed. The ball in this problem has a mass of m=0.2 kg and a kinetic energy of K=40 J, so we can rearrange the previous equation to find its speed:

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4 0
3 years ago
As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near the center o
MrRa [10]

Answer:

18.6012339739 A

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\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

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I = Current

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The current necessary to produce this field is 18.6012339739 A

7 0
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